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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

A boy multiplied 987 by a certain number and obtained 559981 as his answer. If in the answer both 98 are wrong and the other digits are correct , then the correct answer would be :

A) 553681 B) 555181
C) 555681 D) 556581
 
Answer & Explanation Answer: C) 555681

Explanation:

987 = 3 * 7 * 47.
So, the required number must be divisible by each one of 3, 7, 47
553681 => (Sum of digits = 28, not divisible by 3)
555181 => (Sum of digits = 25, not divisible by 3)
555681 is divisible by each one of 3, 7, 47.

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Filed Under: Numbers

61 36489
Q:

Aizaz was born on 5th January 2015, while Faiz was born 553days later. On which date was Faiz born?

 

A) 11th July 2016 B) 10th July 2016
C) 9th July 2016 D) 12th July 2016
 
Answer & Explanation Answer: A) 11th July 2016

Explanation:
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Filed Under: Calendar
Exam Prep: Bank Exams

51 36418
Q:

Which of the following fractions is greater than  3 /4 and less than 5 / 6 ?

A) 3 / 5 B) 4 / 5
C) 7 / 5 D) 9 / 5
 
Answer & Explanation Answer: B) 4 / 5

Explanation:

3 /4 = 0.75, 5/6 = 0.833, 1/2 = .5, 2/3 = 0.66, 4/5 = 0.8, 9/10 = 0.9.

clearly 0.8 lies between 0.75 and .833.

4/5 lies between 3/4 and 5/6..

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Filed Under: Decimal Fractions

56 36401
Q:

The Indian Cricket team consists of 16 players. It includes 2 wicket keepers and 5 bowlers. In how many ways can a cricket eleven be selected if we have to select 1 wicket keeper and atleast 4 bowlers?

A) 1024 B) 1900
C) 2000 D) 1092
 
Answer & Explanation Answer: D) 1092

Explanation:

We are to choose 11 players including 1 wicket keeper and 4 bowlers  or, 1 wicket keeper and 5 bowlers.

 

Number of ways of selecting 1 wicket keeper, 4 bowlers and 6 other players in 2C1*5C4*9C6 = 840

 

Number of ways of selecting 1 wicket keeper, 5 bowlers and 5 other players in 2C1*5C5*9C5 =252

 

Total number of ways of selecting the team = 840 + 252 = 1092

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Filed Under: Permutations and Combinations

35 36349
Q:

Read the data given and answer the following questions

 

In a class of 60 students:

 

42 like Maths,

32 like English,

12 like neither Maths nor English

 

How many students like exactly one subject?

A) 16 B) 12
C) 6 D) 22
 
Answer & Explanation Answer: D) 22

Explanation:
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Filed Under: Percentage
Exam Prep: Bank Exams

2 36321
Q:

1100 boys and 700 girls are examined in a test; 42% of the boys and 30% of the girls pass. The percentage of the total who failed is :

A) 58 B) 62 *2/3
C) 64 D) 67
 
Answer & Explanation Answer: B) 62 *2/3

Explanation:

Total number of students = 1100 + 700 = 1800.

Number of students passed = (42% of 1100 + 30% of 700) - (462 + 210) = 672.

Number of failues = 1800-672 = 1128.

Percentage failure = (1128/1800 * 100 )% = 62 * 2/3 %. 

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Filed Under: Percentage

102 36243
Q:

The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is :

A) 20 B) 21
C) 23 D) 24
 
Answer & Explanation Answer: B) 21

Explanation:

 Lot the total number of workers be v Then,

8OOOv = (12000 * 7) + 6000 (v - 7) <=>  2000v = 42000  <=>  v = 21.

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Filed Under: Average

65 36235
Q:

2 men and 7 boys can do a piece of work in 14 days; 3 men and 8 boys can do the same in 11 days. Then, 8 men and 6 boys can do three times the amount of this work in 

A) 18 days B) 21 days
C) 24 days D) 30 days
 
Answer & Explanation Answer: B) 21 days

Explanation:

(2 x 14) men +(7 x 14) boys = (3 x 11) men + (8 x 11) boys

 =>5 men= 10 boys    => 1man= 2 boys

 Therefore, (2 men+ 7 boys) = (2 x 2 +7) boys = 11 boys

 

( 8 men + 6 boys) = (8 x 2 +6) boys = 22 boys.

 Let the required  number of days be x.

 More boys , Less days     (Indirect proportion)

 More work , More days    (Direct proportion)

 Boys22:11Work1 : 3⋮⋮ 14:x

 Therefore, (22 * 1 * x) = (11 * 3 * 14)

=> x = 21 

Hence, the required number of days = 21

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Filed Under: Chain Rule

90 36222