6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

In the following question, select the odd letter/letters from the given alternatives.

A) CDFI	B) HIKN
C) JKMP	D) LMPS

Answer & Explanation Answer: D) LMPS

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

1 36180

Q:

The difference between the place value and the face value of 7 in the numeral 967452 is

A) 6393	B) 5831
C) 6993	D) 6339

Answer & Explanation Answer: C) 6993

Explanation:

(Place value of 7)-(face value of 7)
=7000-7=6993.

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Filed Under: Numbers

106 36180

Q:

If the pice of sugar rises from Rs. 6 per kg to Rs. 7.50 per kg, a person, to have no increase in his expenditure on sugar, will have to reduce his consumpion of sugar by

A) 15	B) 20
C) 25	D) 30

Answer & Explanation Answer: B) 20

Explanation:

Let original consumption = 100 kg and new consumption = x kg,

So, 100 * 6 = x * 7.50 => x = 80kg

Reduction in consumption = 20%.

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Filed Under: Percentage

108 36158

Q:

Find the surface area (in sq.cm) of a sphere of diameter 14 cm.

A) 616	B) 4699
C) 8628	D) 6922

Answer & Explanation Answer: A) 616

Explanation:

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

3 36100

Q:

Find the odd word/letters/number pair from the given alternatives.

(A) AE (B) CG (C) JN (D) MO

A) A	B) B
C) C	D) D

Answer & Explanation Answer: D) D

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

1 36037

Q:

The length and breadth of a rectangle are 21 cm and 20 cm respectively. Find its area (in cm2).

A) 420	B) 840
C) 80	D) 160

Answer & Explanation Answer: A) 420

Explanation:

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Filed Under: Area
Exam Prep: Bank Exams

0 36012

Q:

Four dice are thrown simultaneously. Find the probability that all of them show the same face.

A) 1/216	B) 1/36
C) 2/216	D) 4/216

Answer & Explanation Answer: A) 1/216

Explanation:

The total number of elementary events associated to the random experiments of throwing four dice simultaneously is:

= $6 * 6 * 6 * 6 = 6^{4}$

n(S) = $6^{4}$

Let X be the event that all dice show the same face.

X = { (1,1,1,1,), (2,2,2,2), (3,3,3,3), (4,4,4,4), (5,5,5,5), (6,6,6,6)}

n(X) = 6

Hence required probability = $\frac{n (X)}{n (S)} = \frac{6}{6^{4}}$ = $\frac{1}{216}$

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Filed Under: Probability

48 35910

Q:

The dimensions of a room are 10m x 7m x 5m. There are 2 doors and 3 windows in the room. The dimensions of the doors are 1m x 3m. One window is of size 2m x 1.5m and the other 2 windows are of size 1m x 1.5m. The cost of painting the walls at Rs. 3 per sq m is

A) Rs.174	B) Rs.274
C) Rs.374	D) Rs.474

Answer & Explanation Answer: D) Rs.474

Explanation:

Area of 4 walls = 2(l+b)h
=2(10+7) x 5 = 170 sq m
Area of 2 doors and 3 windows = 2(1x3)+(2x1.5)+2(1x1.5) = 12 sq m
area to be planted = 170 -12 = 158 sq m

Quantitative Aptitude - Arithmetic Ability Questions

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