Quantitative Aptitude - Arithmetic Ability Questions

Q:

If cot(A/2) = x, then x is equal to

A) tanA/(1 + secA) B) 1/(secA + cotA)
C) tanA/(1 + cosecA) D) 1/(cosecA ­- cotA)
 
Answer & Explanation Answer: D) 1/(cosecA ­- cotA)

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: Bank Exams

0 1386
Q:

If secA -­ tanA = x, then the value of x is

A) √[(1 + sinA)/(1 ­- sinA)] B) √[(1­-sinA)/(1+sinA)]
C) (1-­sinA)/(1+sinA) D) (1 + sinA)/(1 -­ sinA)
 
Answer & Explanation Answer: B) √[(1­-sinA)/(1+sinA)]

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams

0 1386
Q:

If  tan2A / (secA -­ 1)2 = x, then the value of x is

A) (1+cosecA) / (1­-cosecA) B) (1+cosA)(1-­cosA)
C) (1+cosA) / (1­-cosA) D) (1+cosecA)(1­-cosecA)
 
Answer & Explanation Answer: C) (1+cosA) / (1­-cosA)

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: Bank Exams

0 1386
Q:

In ΔXYZ measure of angle Y is 90 deg. If cot X = 5/12, and XY = 2.5 cm, then what is the length (in cm) of side XZ?

A) 6 B) 4
C) 5.6 D) 6.5
 
Answer & Explanation Answer: D) 6.5

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: Bank Exams , CAT

0 1386
Q:

If ab+ba = -1, then the value of a2b-b2a is

A) 1 B) -1
C) 0 D) 2
 
Answer & Explanation Answer: C) 0

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: Bank Exams

0 1386
Q:

The area of a semicircle is 308 sq.cm. Calculate its perimeter (in cm)

A) 144 B) 49
C) 98 D) 72
 
Answer & Explanation Answer: D) 72

Explanation:
Report Error

View Answer Report Error Discuss

0 1386
Q:

10 persons can do a job in X days. If 20 persons with twice the efficiency can do the same job in 5 days, then find the value of X?

A) 40 B) 15
C) 20 D) 30
 
Answer & Explanation Answer: C) 20

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Time and Work
Exam Prep: Bank Exams

0 1385
Q:

A mixture of 50 kg of cement and gravel contains 10% of gravel. How many kg of gravel must be added to make the gravel content 28% in the new mixture?

 

A) 14.5 B) 10.5
C) 12.5 D) 17.5
 
Answer & Explanation Answer: C) 12.5

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Alligation or Mixture
Exam Prep: Bank Exams , CAT

3 1385