Questions

Bond Order  = 1/2[ Nb - Na]

where

Nb = Number of electrons in bonding molecular orbitals.

Na = Number of Electrons in antibonding molecular orbitals

Bond Order of N2⁺:

Total number of electrons: 13

Electronic Configuration= :σ1s² σ*1s² σ2s² σ*2s² π 2py² [π2pz² σ2px1 ]

Bond Order = [9-4]/2 = 5/2 = 2.5.

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