FACTS  AND  FORMULAE  FOR  AREA  QUESTIONS

 

 

FUNDAMENTAL CONCEPTS :

I. Results on Triangles:

1. Sum of the angles of  a triangle is 180o

2. The sum of any two sides of a triangle is greater than the third side.

3. Pythagoras Theorem : In a right - angled triangle,

Hypotenuse2=Base2+Height2

4. The line joining the mid-point of a side of a triangle to the opposite vertex is called the median.

5. The point where the three medians of a triangle meet, is called Centroid. The centroid divides each of the medians in the ratio 2 : 1.

6. In an Isosceles triangle, the altitude from the vertex bisects the base.

7. The median of a triangle divides it into two triangles of the same area.

8. The area of the triangle formed by joining the mid-points of the sides of a given triangle is one-fourth of the area of the given triangle.

 

II.Results on Quadrilaterals :


1. The diagonals of a parallelogram bisect each other

2. Each diagonal of a parallelogram divides it into two triangles of the same area.

3. The diagonals of a rectangle are equal and bisect each other.

4. The diagonals of a square are equal and bisect each other at right angles

5. The diagonals of a rhombus are unequal and bisect each other at right angles

6. A parallelogram and a rectangle on the same base and between the same parallels are equal in area.

7. Of all the parallelogram of given sides, the parallelogram which is a rectangle has the greatest area.

 

IMPORTANT FORMULAE

I. 

1. Area of a rectangle = (length x Breadth)

Length =AreaBreadth  and  Breadth=AreaLength

2. Perimeter of a rectangle = 2( length + Breadth)

 

 

II. Area of square = side2=12diagonal2 

 

III. Area of 4 walls of a room = 2(Length + Breadth) x Height

 

 

IV.

1. Area of a triangle =12×base×height

2. Area of a triangle = s(s-a)(s-b)(s-c), where a, b, c are the sides of the triangle and s=12a+b+c

3. Area of an equilateral triangle =34×side2

4. Radius of incircle of an equilateral triangle of side a=a23

5. Radius of circumcircle of an equilateral triangle of side a=a3

6. Radius of incircle of a triangle of area  and semi-perimeter s=s

 

 

V.

1. Area of a parallelogram = (Base x Height)

2. Area of a rhombus = 12×Product of diagonals

3. Area of a trapezium = 12×(sum of parallel sides)×distance between them

    

 

VI.

1. Area of a cicle = πR2, where R is the radius.

2. Circumference of a circle = 2πR.

3. Length of an arc = 2πRθ360, where θ is the central angle.

4. Area of a sector = 12arc×R=πR2θ360 

 

VII.

1. Area of a semi-circle = πR22

2. Circumference of a semi - circle = πR

Q:

PQRS is a square whose side is 20 cm. By joining opposite vertices of PQRS are get four triangles. What is the sum of the perimeters of the four triangles?

A) 40√2 B) 80√2 + 80
C) 40√2 + 40 D) 40√2 + 80
 
Answer & Explanation Answer: B) 80√2 + 80

Explanation:
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Q:

In the given figure, ABCDEF is a regular hexagon whose side is 6 cm. APF, QAB, DCR and DES are equilateral triangles. What is the area (in sq.cm) of the shaded region?

A) 24√3 B) 18√3
C) 72√3 D) 36√3
 
Answer & Explanation Answer: C) 72√3

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Q:

The base of a parallelogram is twice its height. If the area of the parallelogram is 338 sq.cm. Find its height?

A) 13 cm B) 14 cm
C) 16 cm D) 12 cm
 
Answer & Explanation Answer: A) 13 cm

Explanation:
Let height =x Then, base =2x
2x * x = 338
=>x=13
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Q:

In the given figure, two identical circles of radius 4 cm touch each other. A and B are the centres of the two circles. If RQ is a tangent to the circle, then what is the length (in cm) of RQ?

A) 3√3 B) 2√6
C) 4√2 D) 6√2
 
Answer & Explanation Answer: C) 4√2

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Q:

The lengths of the diagonals of a rhombus are 8 cm and 6 cm. The area of rhombus is:

A) 96 cm2 B) 60 cm2
C) 48 cm2 D) 24 cm2
 
Answer & Explanation Answer: D) 24 cm2

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Q:

ABC is a triangle. AB = 5 cm, AC = √41 cm and BC = 8 cm. AD is perpendicular to BC. What is the area (in cm2) of triangle ABD?

A) 12 B) 6
C) 10 D) 20
 
Answer & Explanation Answer: B) 6

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Q:

What is the measure of an interior angle of a regular decagon?

A) 120° B) 140°
C) 144° D) 150°
 
Answer & Explanation Answer: C) 144°

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Q:

The perimeter of a rectangle whose length is 6 metre more than its breadth is 84 metre. What is the area of the triangle whose base is equal to the diagonal of the rectangle and height is equal to the length of the rectangle?

A) 360sq metre B) 380 sq metre
C) 360 metre D) 400 sq metre
 
Answer & Explanation Answer: A) 360sq metre

Explanation:

Let the breadth of rectangle be x m.

Then, the length of rectangle = (x+ 6) m

Perimeter of rectangle = 2 (x+x+ 6) m

Therefore, 2 (x+x+ 6) = 84 m

4x+ 12 = 84

4x= 84 –12
4x = 72/4 = 18
Therefore, length of rectangle = 18 + 6 = 24 m = height of triangle

Diagonal of rectangle = √(324+576) = 30 m = base of triangle

Therefore, are of triangle =1/2× base × height =1/2× 24 × 30 = 360 sq. m

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