Arithmetical Reasoning Questions

The total cards in the deck are 52. These 52 cards are divided into 4 suits of 13 cards in each suit. Two Red suits and Two black suits.

Red suits :: Heart suit and Diamond suit = 26

Black suits :: Spade suit and Club suit = 26.

Technically or logically it is possible only once. As if you subtract 5 from 25 at first te result will be 20. Now, you can't subtract 5 from 25 since the left number is 20.

But if you go mathematically, it can be done infinite times and only 5 times without going into the negatives.

Here given formula is 

a2 + b2 + c2 -ab- bc - ca = 0

and it is possible if and only if a = b = c.

From the trial and error method, 

1) Let a = b = c = 1

Now substitute these values of a, b, c in the above formula.

We get 1 + 1 + 1 - 1 - 1 - 1 = 3 - 3 = 0

2) Now, let a = b = c = 4

Now substitute these values of a, b, c in the above formula.

We get 16 + 16 + 16 - 16 - 16 - 16 = 48 - 48 = 0.

Hence, it is possible that 

a2 + b2 + c2 -ab- bc - ca = 0 iff a = b = c.

A tangent contains ZERO chords, as it touches the circle at only one point.

Hence, it does not contain any chord.

Let R, G and B represent the number of balls in red, green and blue boxes respectively.

Then, .

R + G + B = 108 ...(i),

G + R = 2B ...(ii)

B = 2R ...(iii)

From (ii) and (iii), we have G + R = 2x 2R = 4R or G = 3R.

Putting G = 3R and B = 2R in (i), we get:

R + 3R + 2R = 108 6R = 108 R = 18.

Therefore Number of balls in green box = G = 3R = (3 x 18) = 54.

Binary system is what the representation uses only two digits 0 & 1.

It uses only the powers of 2.