FACTS  AND  FORMULAE  FOR  PERCENTAGE  QUESTIONS

 

 

I.Concept of Percentage : By a certain percent , we mean that many hundredths. Thus x percent means x hundredths, written as x%.

To express x% as a fraction : We have , x% = x/100.

Thus, 20% = 20/100 = 1/5;     

48% = 48/100 = 12/25, etc.

To express a/b as a percent : We have, ab=ab×100% .

 

Thus, 14=14×100%=25%

   

 

II. If the price of a commodity increases by R%, then the reduction in consumption so as not to increase the expenditure is R100+R×100%

If the price of the commodity decreases by R%,then the increase in consumption so as to decrease the expenditure is R100-R×100%

 

 

III. Results on Population : Let the population of the town be P now and suppose it increases at the rate of R% per annum, then :

1. Population after n years = P1+R100n

 

2. Population n years ago =  P1+R100n

 

 

IV. Results on Depreciation : Let the present value of a machine be P. Suppose it depreciates at the rate R% per annum. Then,

1. Value of the machine after n years = P1-R100n

 

2. Value of the machine n years ago = P1-R100n

 

 

V. If A is R% more than B, then B is less than A by

R100+R×100%    

If A is R% less than B , then B is more than A by 

R100-R×100%  

Q:

Jalal, Amit and Feroz enter into partnership. Jalal invests 4 times as much as Amit and Amit invests three-fourth of what Feroz invests. At the end of the financial year, the total profit earned is Rs. 19,000. Find the share for Jalal.

A) Rs. 15000 B) Rs. 12000
C) Rs. 13000 D) Rs. 10000
 
Answer & Explanation Answer: B) Rs. 12000

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Q:

Each question contains Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.

Quantity I: if the length of a rectangle is increased by 20% while the breadth of the rectangle is decreased by 10% then find percentage change in area of the rectangle?

Quantity II: if the side of a triangle is increased by 30% while the height of a triangle is decreased by 20% then find the percentage change in area of the triangle?

A) Quantity I > Quantity II B) Quantity I ≥ Quantity II
C) Quantity I< Quantity II D) Quantity I < Quantity II
 
Answer & Explanation Answer: A) Quantity I > Quantity II

Explanation:

Quantity I= 20% - 10% - (20*10/100) % = +8%

Quantity II= 30% - 20% - (30*20/100)% = +4%

Hence Quantity I > Quantity II

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Q:

An engineering student has to secure 36% marks to pass. He gets 53 and fails by 37 marks. Find the maximum marks.

A) 275 marks B) 250 marks
C) 300 marks D) 325 marks
 
Answer & Explanation Answer: B) 250 marks

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Q:

Two baskets together have 640 oranges. If (1/5)th of the oranges in the first basket be taken to the second basket. The number of oranges in the first basket is

A) 800 B) 600
C) 400 D) 300
 
Answer & Explanation Answer: C) 400

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Q:

90% of X = 40% of Y and Y = a% of X. What is the value of a?

A) 225 B) 125
C) 2.25 D) 1.25
 
Answer & Explanation Answer: A) 225

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Q:

After two successive discounts of 20% and 35%, an article is sold for Rs 50700. What is the marked price (in Rs) of the article?

A) 92500 B) 98500
C) 97500 D) 94000
 
Answer & Explanation Answer: C) 97500

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Q:

The marked price of an article is Rs. 5000. But due to a special festive offer a certain percent of discount is declared. Mr. X availed this oppurtunity and bought the article at reduced price. He then sold it at Rs. 5000 and thereby made a profit of 11 1/9%. The percentage of discount allowed was?

A) 10 B) 10/3
C) 15/2 D) 100/9
 
Answer & Explanation Answer: A) 10

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Q:

The list price (marked price ) of an article is Rs. 900 and is available at two successive discounts of 20% and 10% ; the selling price of the article,in rupees, is

A) 640 B) 648
C) 720 D) 738
 
Answer & Explanation Answer: B) 648

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