Problems on Ages Questions

Q:

Mohan was married 5 years ago. At present his age is 6/5 times of his age at the time of marriage. His wife is 3 year younger to him. Find his wife’s present age?

A) 21 yrs B) 24 yrs
C) 27 yrs D) 30 yrs
 
Answer & Explanation Answer: C) 27 yrs

Explanation:

Let Mohan present age = p

ATQ,

5/6 x p = p - 5

p = 30

His wifes age = 30 - 3 = 27 yrs.

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Q:

Ten years ago, A was half of B in age. If the ratio of their present ages is 3:4, then what will be the total of their present ages?

Answer

Let A's age 10 years ago be x years . Then B's age 10 years ago be 2x years





 Total of their present ages = x + 10 + 2x + 10


= 3x+20


= 3 * 5 + 20 = 35 years


 

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Q:

The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A ?

A) 12 B) 13
C) 14 D) 15
 
Answer & Explanation Answer: A) 12

Explanation:

(A+B) - (B-C) = 12 <=> A - C = 12.

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Q:

The ratio between present ages of Renuka and Sony is 5 : 4 . 4 years ago, Sony's age was 24 years. What will be Renuka's age after 5 years ?

A) 25 B) 30
C) 35 D) 40
 
Answer & Explanation Answer: D) 40

Explanation:

Present age of Sony = 24 + 4 = 28 years

After 5 years Renuka's age = 7×5 + 5 = 40 years

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Q:

Mary is 12 years younger to Pinky. After 3 years, the ratio of their ages will be 5:8. If the present age of Sam is the sum of ages of Mary and Pinky, then what was the age of Sam 15 years back ?

A) 31 years B) 37 years
C) 46 years D) 29 years
 
Answer & Explanation Answer: A) 31 years

Explanation:

Let the present age of Pinky be x years

 

Then the age of Mary is x - 12 years

 

After 3 years,

 

Ratio of  MaryPinky = x - 9x + 3 = 58

 

8x - 72 = 5x +15

 

=> 3x = 87

 

=> x = 29

 

=> Age of Pinky = 29 years

 

=> Age of Mary = 29 - 12 = 17 years

 

Present age of Sam = 29 + 17 = 46

 

Before 15 years Sam age = 46 - 15 = 31 years.

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Q:

The sum of the present ages of a father and his son is 126 years. 8 years ago their respective ages were in the ratio of 7 : 4. After 7 years what will be the ratio of ages of father and son?

 

A) 23 : 19 B)  17 : 11
C)  27 : 20 D) 34 : 23
 
Answer & Explanation Answer: B)  17 : 11

Explanation:
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Q:

Eighteen years ago, a mother was three times as old as her daughter. Now the mother is only twice as old as her daughter. Then the sum of the present ages of daughter and the mother is ?

A) 84 yrs B) 96 yrs
C) 116 yrs D) 108 yrs
 
Answer & Explanation Answer: D) 108 yrs

Explanation:

Let the present ages of the mother and daughter be 2x and x years respectively.
Then, (2x - 18) = 3(x - 18) => x = 36
Required sum = (2x + x) = 108 years.

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Q:

The present ages of Kavitha, Rajitha and Haritha are in the ratio of 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).

A) 16,36,28 B) 16,28,36
C) 20,35,45 D) 12,21,27
 
Answer & Explanation Answer: B) 16,28,36

Explanation:
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