Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

Given w = -2, x = 3, y = 0 & z = -1/2, find the value of w2(z2 + y2)

 

A) +-2 B) -2
C) 2 D) 4
 
Answer & Explanation Answer: C) 2

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Q:

What is the value of 5123 + 169 + 2163 + 225 ?

 

A) 48 B) 32
C) 42 D) 36
 
Answer & Explanation Answer: C) 42

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Q:

Solve the following

 

36- [18 - {14 - (15 - 4 / 2 x 2)}]

 

 

A) 23 B) 21
C) 20 D) 22
 
Answer & Explanation Answer: B) 21

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Q:

If y - 1y  = 4, then find the value of y3 - 1y3.

 

A) 64 B) 76
C) 88 D) 90
 
Answer & Explanation Answer: B) 76

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Q:

Select the option that can replace the question mark (?) in the following equation.

 

0.23 - 0.130.2 + 0.12

 

A) 1/18 B) 3/40
C) -7/90 D) 7/90
 
Answer & Explanation Answer: D) 7/90

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Q:

Correct expression of 0.018¯ = ?

 

A) 1/55 B) 18/100
C) 18/1000 D) 1/66
 
Answer & Explanation Answer: C) 18/1000

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Q:

What will be the value of that smallest positive integer N, such that 294N is an integer?

 

A) 2 B) 4
C) 6 D) 8
 
Answer & Explanation Answer: C) 6

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Q:

Use continuity to evaluate the limit.

limx128+x8+x

 

A) 1 B) 2
C) 4 D) 0
 
Answer & Explanation Answer: A) 1

Explanation:

Since, we have that,

The numerator and denominator is (8+x), which is a polynomial is continuous for all the real numbers i.e. for all x belonging to .

Thus, the limit exists and is given by,

limx128+x8+x = 8+128+12= 1.

 

 

 

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