Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

If 7x + 9y3x - 4y = 198, then the value of x/y is

 

A) 148/1 B) 1/148
C) 145/1 D) 1/145
 
Answer & Explanation Answer: A) 148/1

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Q:

If 4x = 10247, then what is the value of x?

 

A) 5/7 B) 4/7
C) 3/7 D) 6/7
 
Answer & Explanation Answer: A) 5/7

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1 50458
Q:

If y = 13 + 23 + 33 + 43 + 53 + 63 then find the value of y - 1.

 

A) 429 B) 439
C) 440 D) 441
 
Answer & Explanation Answer: C) 440

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Q:

ΔABC is right angled at B. If cotA = 8/15, then what is the value of cosC ?

 

A) 15/8   B) 8/17  
C) 17/15   D) 15/17
 
Answer & Explanation Answer: D) 15/17

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0 50129
Q:

If Sinx = 4/5, then 1 + Tan2x =

 

A) 9/25 B) 25/16
C) 4/25 D) 25/9
 
Answer & Explanation Answer: D) 25/9

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1 50071
Q:

Solve the following

78 ÷[-4 + -3 of 27 ÷ -18 ÷ -2]

A) -6 B) 13
C) 6 D) 15.6
 
Answer & Explanation Answer: A) -6

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0 50014
Q:

Correct expression of 0.018¯ = ?

 

A) 1/55 B) 18/100
C) 18/1000 D) 1/66
 
Answer & Explanation Answer: C) 18/1000

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Q:

Use continuity to evaluate the limit.

limx128+x8+x

 

A) 1 B) 2
C) 4 D) 0
 
Answer & Explanation Answer: A) 1

Explanation:

Since, we have that,

The numerator and denominator is (8+x), which is a polynomial is continuous for all the real numbers i.e. for all x belonging to .

Thus, the limit exists and is given by,

limx128+x8+x = 8+128+12= 1.

 

 

 

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