Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

If cot 240° = x, then the value of x is

A) -1 B) -1/√3
C) 1/√3 D) √3
 
Answer & Explanation Answer: C) 1/√3

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Q:

If 2(3x ­- 4) -­ 2 < 4x ­- 2 ≥ 2x -­ 4; then the value of x is

A) 2 B) 5
C) -4 D) -5
 
Answer & Explanation Answer: A) 2

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Q:

If 3x + 2 ≥ x - ­1 and 2x -­ 4 ≤ 2 - ­x/3; then x can take which of the following values?

A) -2 B) 3
C) 5 D) -1
 
Answer & Explanation Answer: D) -1

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Q:

What are the co­ordinates of the mid point of the segment joining points C(5,­-2) and D(­-1,8).

A) (­-2, ­3) B) (2, 3)
C) (­2, -3) D)  (-2, -­3)
 
Answer & Explanation Answer: B) (2, 3)

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Q:

One of the roots of the equation x2 - 4x + k = 0 is x = 3. The other root is

A) x = -1 B) x = -4
C) x = 1 D) x = 4
 
Answer & Explanation Answer: C) x = 1

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Q:

The value of 122 + 345 - 3 / 1116 x 372 is

A) 466 B) 469
C) 446 D) 460
 
Answer & Explanation Answer: A) 466

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Q:

The factors of x2 + 8x + 12 are

A) (x+6)(x+2) B) (x-6)(x+2)
C) (x-4)(x-4) D) (x+6)(x-2)
 
Answer & Explanation Answer: A) (x+6)(x+2)

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Q:

If (1 + cosA)/(1 - cosA) = x, then x is

A) cot2A/(secA - 1)2 B) cot2A/(secA + 1)2
C) tan2A/(secA + 1)2 D) tan2A/(secA - 1)2
 
Answer & Explanation Answer: D) tan2A/(secA - 1)2

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