Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

If a + b + c = 11 and ab + bc + ca = 17, then what is the value of a3 + b3 + c3  3abc?

A) 121 B) 168
C) 300 D) 770
 
Answer & Explanation Answer: D) 770

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Q:

If 2x - 3(2x - 2) > x - 1 < 2 + 2x; then x can take which of the following values?

A) 2 B) -2
C) 4 D) -4
 
Answer & Explanation Answer: B) -2

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Q:

If a2+b2=80 and ab = 32, then calculate the value of a-b/a+b.

A) 0.337 B) 0.339
C) 0.333 D) 0.335
 
Answer & Explanation Answer: C) 0.333

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Q:

What approximate value should come in place of the question mark (?) in the following equation (Note: You are not expected to calculate the exact value)?(55.01+16.0003)×22.01÷10.998 =?

A) 190 B) 130
C) 110 D) 142
 
Answer & Explanation Answer: D) 142

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Q:

If cosθ1-sinθ+cosθ1+sinθ = 4, then the value of θ (0°<θ<90°)?

A) 60° B) 45°
C) 30° D) 35°
 
Answer & Explanation Answer: A) 60°

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Q:

Calculate the value of 61681x61681-31681x3168130000

A) 93352 B) 94362
C) 93362 D) 95362
 
Answer & Explanation Answer: C) 93362

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Q:

If 3 tan θ = cot θ where 0 < θ < π/2, then what is the value of θ ?

A) π/6 B) π/4
C) π/2 D) 1
 
Answer & Explanation Answer: A) π/6

Explanation:
3tan θ = cot θ 
3tan θ = 1/tan θ
tan2θ = 1/3
tan θ = 1/√3
θ = π/6
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Q:

If a+b+c = 0, then (a^3 + b^3 + c^3)^2 = ?

A) 27abc B) 9abc
C) 3abc D) 9a^2b^2c^2
 
Answer & Explanation Answer: D) 9a^2b^2c^2

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