Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

What is the reflection of the point (4 , -3) in the line y = 1?

A) (4, -5) B) (4, 5)
C) (-4, -5) D) (-4, 5)
 
Answer & Explanation Answer: B) (4, 5)

Explanation:
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Q:

A fraction is greater than its reciprocal by (72)/(77). What is the fraction?

A) 7/11 B) 11/7
C) 4/7 D) 7/4
 
Answer & Explanation Answer: B) 11/7

Explanation:
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Q:

If SinX-CosX=1, where 'X' is an acute angle, the value of SinX+CosX is

A) 0 B) 1
C) 1/2 D) 2
 
Answer & Explanation Answer: B) 1

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Q:

If x+1x 0 and x3+1x3 = 0, then the value of x+1x4 is :

A) 9 B) 12
C) 15 D) 16
 
Answer & Explanation Answer: A) 9

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Q:

If x + 1/x = 6, then value of x2 + 1/x2 is

A) 23 B) 16
C) 34 D) 32
 
Answer & Explanation Answer: C) 34

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Q:

Square of (3x – 5xy) is

A) 9x2 - 30x2y + 25x2y2 B) 9x2 - 15x2y + 25x2y2
C) 25x2 - 15x2y + 9x2y2 D) 25x2 - 30x2y + 9x2y2
 
Answer & Explanation Answer: A) 9x2 - 30x2y + 25x2y2

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Q:

What is the value of tan 1° tan 2° tan 3°....... tan 89°?

A) 0 B) 1
C) 2 D) infinity
 
Answer & Explanation Answer: B) 1

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Q:

If 3 tan θ = cot θ where 0 < θ < π/2, then what is the value of θ ?

A) π/6 B) π/4
C) π/2 D) 1
 
Answer & Explanation Answer: A) π/6

Explanation:
3tan θ = cot θ 
3tan θ = 1/tan θ
tan2θ = 1/3
tan θ = 1/√3
θ = π/6
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