Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

What is the value of xy if x - y = 3 and x2+y2=15?

A) 1 B) 3
C) 5 D) 7
 
Answer & Explanation Answer: B) 3

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Q:

What is the value of Sin 30- √2 Cos 30

A) (1 - √6)/√2 B) (1 - √6)/2
C) (3 - √6)/2 D) (3 - √6)/√2
 
Answer & Explanation Answer: B) (1 - √6)/2

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Q:

The average of 100 observations was calculated as 35.It was found later, that one of the observation was misread as 83 instead of 53. The correct average is :

A) 32.7 B) 34.7
C) 35.7 D) 36.7
 
Answer & Explanation Answer: B) 34.7

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Q:

If 5/2 - (6/5)(x - 15/2) = -x/5, then what is the value of x?

A) -23/2 B) 13/2
C) -13/2 D) 23/2
 
Answer & Explanation Answer: D) 23/2

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Q:

If (1 - sinA)/(1 + sinA) = x, then x is

A) (cosecA - cotA)2 B) secA - tanA
C) (secA - tanA)2 D) cosecA - cotA
 
Answer & Explanation Answer: C) (secA - tanA)2

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Q:

Find the value of x if 1-x24 = 1318

A) 155 B) 157
C) 159 D) 161
 
Answer & Explanation Answer: A) 155

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Q:

If secA = x, then the value of x is

A) √(1 -­ cot2A) B) √(1 -­ tan2A)
C) √(1 + cot2A) D) √(1 + tan2A)
 
Answer & Explanation Answer: D) √(1 + tan2A)

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Q:

If a + b + c + d = 4, then the value of 1(1-a)(1-b)(1-c) + 1(1-b)(1-c)(1-d) + 1(1-c)(1-d)(1-a) + 1(1-d)(1-a)(1-b)

A) 0 B) 1
C) 4 D) 1+ abcd
 
Answer & Explanation Answer: A) 0

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