Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

When [x + (1/x)] = 5, then what is the value of [x – (1/x)]?

A) 11 B) ± √22
C) 21 D) ± √21
 
Answer & Explanation Answer: D) ± √21

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Q:

If x tan 60° + cos 45° = sec 45° then the value of x2 + 1 is

A) 6/7 B) 7/6
C) 5/6 D) 6/5
 
Answer & Explanation Answer: B) 7/6

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Q:

Simplify (b5x2a3z4)*(b3x2a4z5) / (a2b3z2)

A) b5x4a5z5 B) b5x4a5z7
C) b5x4a4z7 D) b4x4a5z7
 
Answer & Explanation Answer: B) b5x4a5z7

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Q:

If Sinx = 4/5, then Sec2x - 1 = ?

A) 16/25 B) 25/9
C) 9/16 D) 16/9
 
Answer & Explanation Answer: D) 16/9

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Q:

What should be added to 3(x­ - 2y) to obtain 2(3x + y) -­ 5(2x + 3)?

A) 8y -­ 7x ­- 15 B) 8y -­ 7x + 15
C) 8y + 7x + 15 D) 8y + 7x -­ 15
 
Answer & Explanation Answer: A) 8y -­ 7x ­- 15

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Q:

If sinθ x cosθ = 1⁄2 . The value of sinθ ­- cosθ is where 0°< θ< 90°

A) 0 B) √2
C) 2 D) 1
 
Answer & Explanation Answer: A) 0

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Q:

Point A divides segment BC in the ratio 4:1. Co-ordinates of B are (6 , 1) and C are (7/2 , 6). What are the co-ordinates of point A?

A) (4 , 3) B) (4 , 5)
C) (2 , 5) D) (3 , 5)
 
Answer & Explanation Answer: B) (4 , 5)

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Q:

If sec2A cosec2A = x, then x is

A) sec2A + cosec2A + 2 B) tan2A + cot2A - 2
C) tan2A + cot2A + 2 D) sec2A + cosec2A - 2
 
Answer & Explanation Answer: C) tan2A + cot2A + 2

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