Time and Distance Questions

FACTS  AND  FORMULAE  FOR  TIME  AND  DISTANCE

1.Speed = DistanceTime,  Time=DistanceSpeed, Distance= Speed×Time 

 

2. x km/hr = x×518 m/sec

 

3. x m/sec = x×185 km/hr

4. If the ratio of the speeds of A and B is a:b , then the ratio of the times taken by them to cover the same distance is or b : a

5. Suppose a man covers a certain distance at x km/ hr and an equal distance at y km/hr . Then, the average speed during the whole journey is 2xyx+ykm/hr.

Q:

Laxmi and Prasanna set on a journey. Laxmi moves northwards at a speed of 20kmph and Prasanna moves southward at a speed of 30 kmph. How far will be Prasanna from Laxmi after 60 minutes ?

A) 24 km B) 50 km
C) 42 km D) 30 km
 
Answer & Explanation Answer: B) 50 km

Explanation:

We know 60 min = 1 hr
Total northward Laxmi's distance = 20kmph x 1hr = 20 km
Total southward Prasanna's distance = 30kmph x 1hr = 30 km
Total distance between Prasanna and Laxmi is = 20 + 30 = 50 km.

Report Error

View Answer Report Error Discuss

Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

3 4526
Q:

An express traveled at an average speed of 100 km/hr, stopping for 4 min after every 75 km. How long did it take to reach its destination 600 km from the starting point ?

A) 6 hrs 24 min B) 6 hrs
C) 7 hrs 21 min D) 6 hrs 28 min
 
Answer & Explanation Answer: D) 6 hrs 28 min

Explanation:

Time taken to cover 600 km = 600/100 = 6 hrs.

Number of stoppages = 600/75 - 1 = 7

Total time of stoppages = 4 x 7 = 28 min

Hence, total time taken = 6 hrs 28 min.

Report Error

View Answer Report Error Discuss

Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

5 4484
Q:

A Bus travels first half distance between two places with a speed of 40 kmph and the rest half distance with a speed of 60 kmph. The average speed of the Bus is ?

A) 48 kmph B) 50 kmph
C) 46 kmph D) 42 kmph
 
Answer & Explanation Answer: A) 48 kmph

Explanation:

we know that speed = distance traveled/time taken
let the total distance traveled by the car is 2x km.
then time taken by it to cover first half is x/60 hour.
and for second half is x/40 hour.
Then average speed= total distance travelled / total time taken.

 

i.e. 2xx60+x40

 

=> 2x5x120

 

= 48 kmph.

Report Error

View Answer Report Error Discuss

Filed Under: Time and Distance
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

1 4477
Q:

A man travels 480 km in 4 hours, partly by air and partly by train. If he had travelled all the way by air, he would have saved 4/5 of the time he would have taken to travel by train and would have arrived at his destination 2 hours early. Find the distance he covered by travelling by train.

A) 80 km B) 120 km
C) 110 km D) 90 km
 
Answer & Explanation Answer: B) 120 km

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Time and Distance
Exam Prep: Bank Exams

23 4404
Q:

A goods truck travels from a place at a certain time and at fixed speed. After 6hrs another truck leaves the same place and move in same direction of uniform speed of 90kmph. The truck catches up the goods truck in 4hrs. Find the speed of the goods truck ?

A) 36 kmph B) 32 kmph
C) 28 kmph D) 34 kmph
 
Answer & Explanation Answer: A) 36 kmph

Explanation:

Let the speed of goods truck be 'p' kmph
Distance covered by goods truck in 10hrs (4+6) = Distance covered by other truck in 4 hrs.
10p = 4 x 90
p = 36kmph.
Therefore, the speed of the goods truck is p = 36 kmph.

Report Error

View Answer Report Error Discuss

Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

6 4114
Q:

Walking at a speed of 10 km/hr, Madhu reaches her university 15 minutes late. Next time she increases her speed by 2 km/hr, but she is still late by 5 minutes. The distance of the university from her house is:

A) 15 km B) 30 km
C) 20 km D) 10 km
 
Answer & Explanation Answer: D) 10 km

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE

12 4006
Q:

Two trains running in opposite directions cross a pole placed on the platform in 47 seconds and 31 seconds respectively. If they cross each other in 33 seconds, what is the ratio of their speeds?

A) 1:7 B) 7:1
C) 2:3 D) 3:2
 
Answer & Explanation Answer: A) 1:7

Explanation:

Let the speed of the trains be x and y respectively
length of train1 = 47x
length of train2 = 31y
Relative speed= x + y
Time taken to cross each other = 33 s
=> 47x+31yx+y= 33
=> (47x + 31 y) = 33(x + y)
=> 14x = 2y
=> x/y = 2/14 = 1/7

 = 1:7

Report Error

View Answer Report Error Discuss

Filed Under: Time and Distance
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

4 3968
Q:

Ali and Faizer are 27m apart. They both start walking and meet 9 hrs later, if they travel in the same direction and meet after 3 hrs if they walk in opposite dirction, Ali’s speed must most likely be ?

A) 9 m/h B) 3 m/h
C) 6 m/h D) 12 m/h
 
Answer & Explanation Answer: C) 6 m/h

Explanation:

let, speed of Ali=X mph and Faizer=Y mph

Now, relative speed when Ali is walking int the same direction with Faizer= (X-Y)mph
hence, according to question, 27/(X-Y)=9 ; solving X-Y=3; --- (1)

Now relative speed when walking in the opposite direction= (X+Y) mph
hence, according to question, 27/(X+y)=3; solving X+Y=9; --- (2)

solving 1 and 2 we get X=6 and Y=3, where X is the speed of Ali.

Report Error

View Answer Report Error Discuss

Filed Under: Time and Distance
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

3 3874