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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

Value of (4a2+ 12ab + 9b2)/(2a + 3b) is

A) 2a - 3b B) 2a + 3b
C) 2a D) 3b
 
Answer & Explanation Answer: B) 2a + 3b

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

0 1868
Q:

A bag has Rs12.9 in the form of 1 rupee, 50 paise and 10 paise coins in the ratio of 3:2:3. How many 50 paise coins are there in the bag?

A) 9 B) 6
C) 12 D) 3
 
Answer & Explanation Answer: B) 6

Explanation:
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Filed Under: Ratios and Proportions
Exam Prep: Bank Exams

2 1868
Q:

If a - b = 10 and ab =-21, then what is the value of a3-b3 ?

A) 316 B) 370
C) 185 D) 158
 
Answer & Explanation Answer: B) 370

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Filed Under: Simplification
Exam Prep: Bank Exams

0 1867
Q:

Select the odd word from the given alternatives

A) Carrot B) Brinjal
C) Radish D) Beet
 
Answer & Explanation Answer: B) Brinjal

Explanation:
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Filed Under: Verbal Reasoning - Mental Ability
Exam Prep: Bank Exams

5 1867
Q:

The monthly expenditure of a person is Rs. 6000. The distribution of expenditure on various items is as follows:

Item of expenditure            Amount(in Rs.)
Food                                      2000
Clothing                                   660
Fuel and rent                          1200
Education                                 480
Miscellaneous                         1660

If the above data is represented by a percentage bar diagram of height 15 cm, then what are the lengths of the two segments of the bar diagram corresponding to education and miscellaneous respectively?

 

A) 1.25 cm and 5 cm B) 1.2 cm and 4.15 cm
C) 1.2 cm and 3.5 cm D) 4.15 cm and 6 cm
 
Answer & Explanation Answer: B) 1.2 cm and 4.15 cm

Explanation:
15 cm corresponds to 6000 rs
Education = 480/6000 * 15 cm = 1.2 cm
Miscellaneous = 1660/6000 * 15 cm = 4.15 cm
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Filed Under: Bar Charts
Exam Prep: Bank Exams

3 1867
Q:

If 17 + 17 = 2895 18 + 18 = 3245 19 + 19 = 3615 then 23 + 23 = ?

A) 5765 B) 2565
C) 4005 D) 5295
 
Answer & Explanation Answer: D) 5295

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Filed Under: Mathematical Operations
Exam Prep: Bank Exams

15 1867
Q:

Kiran swims in a 90 m long pool. He covers 360 m in two minutes by swimming from one end to the other and back 0 along the same straight path, twice. Find the average speed of Kiran.

A) 4 m/s B) 6 m/s
C) 3 m/s D) 8 m/s
 
Answer & Explanation Answer: C) 3 m/s

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Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT

0 1867
Q:

In the question given below, two equations are provided. Solve the equations and establish the relationship between x and y

I. 2x2-13x-189=0 II. 2y2-3y-189=0

A) x>y B)  x≥y
C)  x<y D) x≤y
 
Answer & Explanation Answer:

Explanation:

I. 2x2 - 13x - 189 = 0 2x2 - 27x + 14x - 189 = 0 x(2x - 27) + 7(2x - 27) = 0 x = -7, 27/2

II. 2y2 - 3y - 189 = 0 2y2 - 21y + 18y - 189 = 0 y(2y - 21) + 9(2y - 21) = 0 y = -9, 21/2

When x, as well as y, have both positive and negative values then no relationship can be established between them because if we consider x to be positive then the negative value of y will be lesser than x. If we consider x to be negative then positive value of y will be greater than x.

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