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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

Four dice are thrown simultaneously. Find the probability that all of them show the same face.

A) 1/216 B) 1/36
C) 2/216 D) 4/216
 
Answer & Explanation Answer: A) 1/216

Explanation:

The total number of elementary events associated to the random experiments of throwing four dice simultaneously is:

 

= 6*6*6*6=64

 

n(S) = 64

 

Let X be the event that all dice show the same face. 

 

X = { (1,1,1,1,), (2,2,2,2), (3,3,3,3), (4,4,4,4), (5,5,5,5), (6,6,6,6)}

 

n(X) = 6

 

Hence required probability = n(X)n(S)=664 =1216

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Filed Under: Probability

48 35830
Q:

Find the odd word/letters/number pair from the given alternatives.

(A) ECBY (B) RTUX (C ) GEDA (D) WUTQ

A) A B) B
C) C D) D
 
Answer & Explanation Answer: B) B

Explanation:
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Filed Under: Odd Man Out
Exam Prep: Bank Exams

0 35825
Q:

Select the related word/letters/number from the given alternatives.

Iron Man Of India : Sardar Vallabhbhai Patel : : Father of the Nation : ?

A) Lokmanya Tilak B) Rajeev Gandhi
C) Jawahar Lal Nehru D) Mahatma Gandhi
 
Answer & Explanation Answer: D) Mahatma Gandhi

Explanation:
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Filed Under: Analogy
Exam Prep: Bank Exams

0 35798
Q:

The dimensions of a room are 10m x 7m x 5m. There are 2 doors and 3 windows in the room. The dimensions of the doors are 1m x 3m. One window is of size 2m x 1.5m and the other 2 windows are of size 1m x 1.5m. The cost of painting the walls at Rs. 3 per sq m is

A) Rs.174 B) Rs.274
C) Rs.374 D) Rs.474
 
Answer & Explanation Answer: D) Rs.474

Explanation:

Area of 4 walls = 2(l+b)h
=2(10+7) x 5 = 170 sq m
Area of 2 doors and 3 windows = 2(1x3)+(2x1.5)+2(1x1.5) = 12 sq m
area to be planted = 170 -12 = 158 sq m

Cost of painting = Rs. 158 x 3 = Rs. 474

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

37 35771
Q:

Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.70 a kg to produce a mixture worth Rs. 6.30 a kg.

A) 1:3 B) 2:3
C) 3:4 D) 4:5
 
Answer & Explanation Answer: B) 2:3

Explanation:

By the rule of alligation:
Cost of 1 kg rice of 1st kind                  Cost of 1 kg rice of 2nd kind 

 

 

  Required ratio = 60 : 90 = 2 : 3

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Filed Under: Alligation or Mixture

66 35769
Q:

The altitude drawn to the base of an isosceles triangle is 8cm and the perimeter is 32cm. Find the area of the triangle?

A) 50 B) 60
C) 70 D) 80
 
Answer & Explanation Answer: B) 60

Explanation:

let ABC be the isosceles triangle, the AD be the altitude 

Let AB = AC = x then BC= 32-2x       [because parameter = 2 (side) + Base] 

since in an isoceles triange the altitude bisects the base so 

BD = DC = 16-x 

In a triangle ADC, AC2=AD2+DC2 

x2=82+16-x2 ⇒x=10 

BC = 32-2x = 32-20 = 12 cm 

Hence, required area = 12*BC*AD= 12*12*10 = 60 sq cm

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

69 35745
Q:

Select the related word/letters/number from the given alternatives.

 

AE : FJ : : ? : PT

 

A) OK B) KO
C) DE D) FG
 
Answer & Explanation Answer: B) KO

Explanation:
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Filed Under: Analogy
Exam Prep: Bank Exams

0 35703
Q:

Select the related word/letters/number from the given alternatives.

 

TN : WQ : : BV : ?

 

A) QT B) LK
C) EY D) EZ
 
Answer & Explanation Answer: C) EY

Explanation:
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Filed Under: Analogy
Exam Prep: Bank Exams

0 35698