5555+ Aptitude and Reasoning Questions, Answers With Explanation

Q:

In how many ways a committee, consisting of 5 men and 6 women can be formed from 8 men and 10 women?

A) 53400	B) 17610
C) 11760	D) 45000

Answer & Explanation Answer: C) 11760

Explanation:

Required number of ways = $(8 C_{5} * 10 C_{6})$ = $(8 C_{3} * 10 C_{4})$ = 11760

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Filed Under: Permutations and Combinations

25 25841

Q:

Sivagami is 2 years elder than Meena. After 6 years the total of their ages will be 7 times of their current age. Then age of Sivagami is :

A) 19 years	B) 17 years
C) 15 years	D) data inadequate

Answer & Explanation Answer: D) data inadequate

Explanation:

Let Meena’s age = A.
Then Sivagami’s age = A + 2
After 6 years the total of their ages will be 7 times of what?
Not clear.
So the given data are inadequate.

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Filed Under: Problems on Ages

49 25813

Q:

Which of the following terms follows the trend of the given list?

QPPPPPP, QQPPPPP, QQQPPPP, QQQQPPP, QQQQQPP, _______________.

A) QQQQQQP	B) PPPPPPP
C) QPPPPPP	D) QQPPPPP

Answer & Explanation Answer: A) QQQQQQP

Explanation:

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Filed Under: Alphabet Test
Exam Prep: Bank Exams

0 25796

Q:

Complete the number series?

11, 12.2, 14.6, 18.2, ?

A) 21.8	B) 23
C) 24.6	D) 25

Answer & Explanation Answer: B) 23

Explanation:

The given number series 11, 12.2, 14.6, 18.2, ?

11

11 + 1.2 = 12.2

12.2 + 2.4 = 14.6

14.6 + 3.6 = 18.2

18.2 + 4.8 = 23

Hence, the next number in the given number series is 23.

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Filed Under: Number Series
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

8 25793

Q:

Statements followed by some conclusions are given below.

Statements :

1. Some football players are cricketers.

2. All hockey players love football though some are cricketers.

Conclusions :

I. Some hockey players who are cricketers play football too.

II. There is at the most one cricketer who plays football and hockey.

Find which of the given conclusions logically follows from the given statements.

A) Only conclusion I follows	B) Only conclusion II follows
C) Both I and II follow	D) Neither I nor II follows

Answer & Explanation Answer: D) Neither I nor II follows

Explanation:

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Filed Under: Statement and Conclusions
Exam Prep: Bank Exams

1 25780

Q:

Study the following table and answer the questions based on it. Expenditures of a Company (in Pesetas) per Annum Over the given Years.

1. What is the average amount of interest per year which the company had to pay during this period?

A. 32.43 B. 33.72 C. 34.18 D. 36.66

2. The total amount of bonus paid by the company during the given period is approximately what percent of the total amount of salary paid during this period?

A. 0.1% B. 0.5% C. 1.0% D. 1.25 %

3. Total expenditure on all these items in 1998 was approximately what percent of the total expenditure in 2002?

A. 62% B. 66% C. 69% D. 71%

4. The total expenditure of the company over these items during the year 2000 is?

A. 544.44 B. 501.11 C. 446.46 D. 478.87

5. The ratio between the total expenditure on Taxes for all the years and the total expenditure on Fuel and Transport for all the years respectively is approximately?

A. 4 : 7 B. 10 : 13 C. 15 : 18 D. 5 : 8

The ratio between the total expenditure on Taxes for all the years and the total expenditure on Fuel and Transport for all the years respectively is approximately? - See more at: https://www.theonlinetestcentre.com/table-charts.html#1

The total expenditure of the company over these items during the year 2000 is? - See more at: https://www.theonlinetestcentre.com/table-charts.html#1

0.1%

What is the average amount of interest per year which the company had to pay during this period? - See more at: https://www.theonlinetestcentre.com/table-charts.html#1

Answer

1. ANSWER : D

Explanation -

Average amount of interest paid by the company during the given period

= $R s . \frac{23.4 + 32.5 + 41.6 + 36.4 + 49.4}{5} l a k h s = R s . \frac{183.3}{5} l a k h s$

= Rs. 36.66 lakhs

2. ANSWER : C

Explanation -

Required Percentage = $\frac{3.00 + 2.52 + 3.84 + 3.68 + 3.96}{288 + 342 + 324 + 336 + 420} \times 100$ %

= $\frac{17}{1710} \times 100$ % $\approx$ 1%

3. ANSWER: C

Explanation -

Required Percentage = $\frac{288 + 98 + 3.00 + 23.4 + 83}{420 + 142 + 3.96 + 49.4 + 98} \times 100$

= $\frac{495.4}{713.36} \times 100$ $\approx$ 69.45%

4. ANSWER: A

Explanation - Total expenditure of the Company during 2000 = (324 + 101 + 3.84 + 41.6 + 74) lakhs = 544.44 lakhs

5. ANSWER : B

Explanation -

Required ratio = $\frac{83 + 108 + 74 + 88 + 98}{98 + 112 + 101 + 133 + 142}$

= $\frac{451}{586}$

= $\frac{1}{1.3} = \frac{10}{13}$

Workspace

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Subject: Table Charts

64 25769

Q:

Find the odd word/letters/number pair from the given alternatives.

(A) KP

(B) MN

(C) HR

(D) GT

A) A	B) B
C) C	D) D

Answer & Explanation Answer: C) C

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

1 25752

Q:

In how many ways can 5 different toys be packed in 3 identical boxes such that no box is empty, if any of the boxes may hold all of the toys ?

A) 36	B) 25
C) 24	D) 72

Answer & Explanation Answer: B) 25

Explanation:

The toys are different; The boxes are identical

If none of the boxes is to remain empty, then we can pack the toys in one of the following ways

a. 2, 2, 1

b. 3, 1, 1

Case a. Number of ways of achieving the first option 2 - 2 - 1

Two toys out of the 5 can be selected in $5 C_{2}$ ways. Another 2 out of the remaining 3 can be selected in $3 C_{2}$ ways and the last toy can be selected in $1 C_{1}$ way.

However, as the boxes are identical, the two different ways of selecting which box holds the first two toys and which one holds the second set of two toys will look the same. Hence, we need to divide the result by 2

Therefore, total number of ways of achieving the 2 - 2 - 1 option is ways $5 C_{2} * 3 C_{2}$ = 15 ways

Case b. Number of ways of achieving the second option 3 - 1 - 1

Three toys out of the 5 can be selected in $5 C_{3}$ ways. As the boxes are identical, the remaining two toys can go into the two identical looking boxes in only one way.

Therefore, total number of ways of getting the 3 - 1 - 1 option is $5 C_{3}$ = 10 = 10 ways.

Total ways in which the 5 toys can be packed in 3 identical boxes

= number of ways of achieving Case a + number of ways of achieving Case b= 15 + 10 = 25 ways.

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Filed Under: Permutations and Combinations

34 25734

Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

Why Aptitude and Reasoning Questions?

What type of questions are there in Aptitude and Reasoning tests?

Non Verbal Reasoning

Quantitative Aptitude - Arithmetic Ability

Quantitative Aptitude - Data Interpretation

Verbal Reasoning - Logical Deduction

Verbal Reasoning - Mental Ability

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