Aptitude and Reasoning Questions

Q:

A sum of Rs.118 was divided among 50 boys and girls such that each boy received Rs.2.60 and each girl Rs.1.80. Find the number of boys and girls ?

Answer

Average money received by each = 118/50 = Rs. 2.36 


 


 Therefore, Ratio of No.of boys and girls = 56 : 24 = 7 : 3


 Therefore, Number of boys = 50 x (7/10) = 35


 Number of girls = 50 - 35 = 15

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56 27983
Q:

Select the number missing from the given series.

 

3, 12, ___, 21612

 

A) 147 B) 149
C) 200 D) 150
 
Answer & Explanation Answer: A) 147

Explanation:
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Filed Under: Number Series
Exam Prep: Bank Exams , CAT

7 27980
Q:

Select the odd term out of the following.

0.02, 0.020, 2/100, 0.002

 

A) 0.002 B) 0.020
C) 0.02 D) 2/100
 
Answer & Explanation Answer: A) 0.002

Explanation:
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Filed Under: Odd Man Out
Exam Prep: Bank Exams

0 27977
Q:

Read the following information and answer the questions given below:

A has 28 elements, B has 32 elements and A U B has 40 elements.

How many elements are present only in B?

A) 28 B) 18
C) 12 D) 10
 
Answer & Explanation Answer: C) 12

Explanation:
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0 27971
Q:

In a queue, Amrita is 10th from the front while Mukul is 25th from behind and Mamta is just in the middle of the two. If there be 50 persons in the queue. What position does Mamta occupy from the front ?

A) 14th B) 16th
C) 18th D) 20th
 
Answer & Explanation Answer: C) 18th

Explanation:

Number of persons between Amrita and Mukul = 50 - (10 + 25) = 15. Since Mamta lies in middle of these 15 persons, so Mamta`s position is 8th from Amrita i.e. 18th from the front.

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102 27969
Q:

If 3!5 = 30, 6!1 = 12 and 5!8 = 80, then find the value of 2!2 = ?

 

A) 28 B) 12
C) 8 D) 32
 
Answer & Explanation Answer: C) 8

Explanation:
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Filed Under: Coding and Decoding
Exam Prep: Bank Exams

2 27963
Q:

Select the figure that does NOT belong in the following group.

 

 

A) B B) D
C) C D) A
 
Answer & Explanation Answer: C) C

Explanation:
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Filed Under: Odd Man Out
Exam Prep: Bank Exams

0 27960
Q:

There are four hotels in a town. If 3 men check into the hotels in a day then what is the probability that each checks into a different hotel?

A) 1/2 B) 3/4
C) 4/7 D) 3/8
 
Answer & Explanation Answer: D) 3/8

Explanation:

Total cases of checking in the hotels = 4 x 4 x 4 = 64 ways.

Cases when 3 men are checking in different hotels = 4×3×2 = 24 ways.

Required probability =24/64  = 3/8

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Filed Under: Probability

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