Aptitude and Reasoning Questions

Q:

Which of the following terms follows the trend of the given list?

XYXYXYxY, XYXYXyXY, XYXYxYXY, XYXyXYXY, XYxYXYXY,  _______________.

A) XXXYYX B) YYXXXX
C) XYYXXX D) XXYYXX
 
Answer & Explanation Answer: B) YYXXXX

Explanation:
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Filed Under: Number Series
Exam Prep: Bank Exams

0 25978
Q:

In how many ways a committee, consisting of 5 men and 6 women can be formed from 8 men and 10 women?

A) 53400 B) 17610
C) 11760 D) 45000
 
Answer & Explanation Answer: C) 11760

Explanation:

Required number of ways = 8C5*10C6 =  8C3*10C4 = 11760

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25 25952
Q:

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days what is time taken by 15 men and 20 boys?

A) 4 days B) 6 days
C) 7 days D) 5 days
 
Answer & Explanation Answer: A) 4 days

Explanation:

Given that 

6 men and 8 boys can do a piece of work in 10 days 

26 men and 48 boys can do the same in 2 days

 

As the work done is equal,

10(6M + 8B) = 2(26M + 48B)

60M + 80B = 52M + 96B

=> M = 2B

=> B = M/2 ……(1)

 

Now Put (1) in 15M + 20B

=> 15M + 10M = 25M

Now, 6M + 8B in 10 days

=> (6M + 4M) 10 = 100M

Then D(25M) = 100M

=> D = 4 days.

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Filed Under: Time and Work
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

33 25938
Q:

A jar was full with honey. A person  used to draw out 20% of the honey from the jar and replaced it with sugar solution. He has repeated  the same process 4 times and thus there was only 512 gm of honey left in the jar, the rest part of the jar was filled with the sugar  solution. The initial amount of honey in the jar was filled with the sugar solution. The initial amount of honey in the jar was:

A) 1.25 kg B) 1 kg
C) 1.5 kg D) None of these
 
Answer & Explanation Answer: A) 1.25 kg

Explanation:

Let the initial amount of honey in the jar was K, then 

 512=K1-154     20% =20100=15

        or      

512=K454

Therefore, K = 1250

Hence initially the honey in the jar= 1.25 kg

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Filed Under: Alligation or Mixture

32 25923
Q:

Select the correct set of symbols which will fit in the given equation?

 

5 0 3 5 = 20

 

A) +, - , + B) x, +, x
C) -, +, x D) x, x, x
 
Answer & Explanation Answer: C) -, +, x

Explanation:
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Filed Under: Coding and Decoding
Exam Prep: Bank Exams

2 25913
Q:

How many such digits are there in the number 7346285 which are as far away from the beginning of the number, as they will be when arranged in ascending order within the number?

A) None B) one
C) Two D) Three
 
Answer & Explanation Answer: C) Two

Explanation:

Given Number : 7346285

Ascending Number : 2345678

Answer is Two. Those digits are 3,4

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Filed Under: Number, Ranking and Time Sequence Test
Exam Prep: Bank Exams
Job Role: Bank PO

143 25911
Q:

Find the missing number in the series.

2, 3, 8, ?, 112, 565

A) 565 B) 112
C) 27 D) 8
 
Answer & Explanation Answer: C) 27

Explanation:
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Filed Under: Number Series
Exam Prep: Bank Exams

2 25889
Q:

A bag contains 600 coins of 25 p denomination and 1200 coins of 50 p denomination. If 12% of 25 p coins and 24% of 50 p coins are removed, the percentage of money removed from the bag is nearly :

A) 21.6 % B) 15.3 %
C) 14.6 % D) 12.5 %
 
Answer & Explanation Answer: A) 21.6 %

Explanation:

Total money = Rs.[600*(25/100)+1200*(50/100)]= Rs. 750.

 

25 paise coins removed = Rs. (600*12/100) = 72.

 

50 paise coins removed = Rs. (1200*24/100)= 288.

 

Money removed =Rs.(72*25/100+288*50/100)  = Rs.162.

 

Required percentage = (162/750*100)% = 21.6 %.

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Filed Under: Percentage

57 25867