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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

A bar graph showing the heights of six mountain peaks. Study the bar graph and answer questions.

Which peak is the second highest ?

A) B B) C
C) A D) E
 
Answer & Explanation Answer: B) C

Explanation:
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Filed Under: Bar Charts
Exam Prep: Bank Exams

3 22373
Q:

What should come in place of question mark (?) in the following number series?

36, 18, 6, 3, 1, ?

A) 0.25 B) 1.5
C) 0.5 D) 0.75
 
Answer & Explanation Answer: C) 0.5

Explanation:

Given number series - 36, 18, 6, 3, 1, ?

 

The pattern is as follows: 36/2 = 18

 

18/3 = 6

 

6/2 = 3

 

3/3=1

 

1/2 = 0.5

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Filed Under: Number Series

1 22368
Q:

One of the roots of the equation x2 - 6x + k = 0 is x = 2. The other root is

 

A) x = -1 B) x = 4
C) x = -4 D) x = 1
 
Answer & Explanation Answer: B) x = 4

Explanation:
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Filed Under: Area
Exam Prep: Bank Exams

1 22325
Q:

What percent of a day is 3 hours?

A) 14.9% B) 12.5%
C) 15.6%% D) 11.4%
 
Answer & Explanation Answer: B) 12.5%

Explanation:

Let p% of a day is 3 hrs.

We know that a day has 24 hrs.

=> p x 24/100 = 3

=> p = 300/24

=> p = 12.5%

 

Hence, 3 hrs is 12.5% of a day.

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

24 22317
Q:

In what time will Rs. 1000 become Rs. 1331 at 10% per annum compounded annually?

A) 1years B) 2years
C) 3years D) 4years
 
Answer & Explanation Answer: C) 3years

Explanation:

Principal = Rs. 1000; Amount = Rs. 1331; Rate = 10% p.a. Let the time be n years. Then,
[ 1000 (1+ (10/100))^n ] = 1331 or (11/10)^n = (1331/1000) = (11/10)^3
n = 3 years

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

39 22305
Q:

In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?

A) 209 B) 290
C) 200 D) 208
 
Answer & Explanation Answer: A) 209

Explanation:

We may have (1 boy and 3 girls) or (2 boys and 2 girls) or (3 boys and 1 girl) or (4 boys). 

 

Required number of ways = 6C1*4C3+6C2*4C2+6C3*4C1+6C4  

= 6C1*4C1+6C2*4C2+6C3*4C1+6C2 = 209.

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Filed Under: Permutations and Combinations

11 22293
Q:

Consider the following statements:

1) The perimeter of a triangle is greater than the sum of its three medinas.

2) In any triangle ABC, if D is any point on BC, then AB + BC + CA > 2AD.

Which of the above statements is/are correct?

A) 1 only B) 2 only
C) Both 1 and 2 D) Neither 1 nor 2
 
Answer & Explanation Answer: C) Both 1 and 2

Explanation:
Let ABC be the triangle and D. E and F are midpoints of BC, CA and AB respectively.
Recall that the sum of two sides of a triangle is greater than twice the median bisecting the third side,(Theorem to be remembered)
Hence in ΔABD, AD is a median
⇒
AB + AC > 2(AD)
Similarly, we get
BC + AC > 2CF
BC + AB > 2BE
On adding the above inequations, we get
(AB + AC) + (BC + AC) + (BC + AB )> 2AD + 2CD + 2BE
2(AB + BC + AC) > 2(AD + BE + CF)
∴
AB + BC + AC > AD + BE +CF
 
2.
To prove: AB + BC + CA > 2AD
Construction: AD is joined
Proof: In triangle ABD,
AB + BD > AD [because, the sum of any two sides of a triangle is always greater than the
third side]
----
1
In triangle ADC,
AC + DC > AD [because, the sum of any two
sides of a tri
angle is always greater than the
third side]
----
2
Adding 1 and 2 we get,
AB + BD + AC + DC > AD + AD
=> AB + (BD + DC) + AC > 2AD
=> AB + BC + AC > 2AD
Hence proved
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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

1 22280
Q:

A sum of money amounts to Rs. 9800 after 5 years and Rs. 12005 after 8 years at the same rate of simple interest. The rate of interest per annum is:

A) 5% B) 8%
C) 12% D) 15%
 
Answer & Explanation Answer: C) 12%

Explanation:

 

S.I. for 3 years = Rs. (12005 - 9800) = Rs. 2205.

 

S.I. for 5 years = Rs.22053×5= Rs.3675

 

Principle = Rs.(9800-3675) = Rs.6125

 

Hence, Rate = 100×36756125×5 =12%

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

18 22278