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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

Some boys are sitting in a row. P is sitting fourteenth from the left and Q is seventh from the right. If there are four boys between P and Q, how many boys are there in the row ?

A) 26 B) 24
C) 25 D) 22
 
Answer & Explanation Answer: C) 25

Explanation:

Number of boys in the row = number of boys uptil P + number of boys between P and Q + number of boys including Q and those behind Q = 14 + 4 + 7 = 25.

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Filed Under: Number, Ranking and Time Sequence Test
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk

69 18454
Q:

The solution of 3(2u + v) = 7 uv and 3(u + 3v) = 11 uv is _____

 

A) u = 1, v = 0 B) u = 1, v = 3/2
C) u = 0, v = 3/4 D) u = 0, v = 1
 
Answer & Explanation Answer: B) u = 1, v = 3/2

Explanation:

Using Trial and error method,

From the options  u = 1, v = 3/2 satisfies both the equations.

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Filed Under: Mathematical Operations
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

37 18452
Q:

Arrange the given words in the sequence in which they occur in the dictionary.

1. Frantic

2. Fraud

3. Fountain

4. Frank

5. Frail

 

A) 54321 B) 52314
C) 35412 D) 24153
 
Answer & Explanation Answer: C) 35412

Explanation:
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Filed Under: Logical Sequence of Words
Exam Prep: Bank Exams

0 18451
Q:

A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train ?

A) 69.5 km/hr B) 70 km/hr
C) 79 km/hr D) 79.2 km/hr
 
Answer & Explanation Answer: D) 79.2 km/hr

Explanation:

Let the length of the train be x metres and its speed by y m/sec.


Then, x/y = 8 => x = 8y


Now, (x+264)/20 = y
8y + 264 = 20y
y = 22.
Speed = 22 m/sec = (22*18/5) km/hr = 79.2 km/hr.

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Filed Under: Problems on Trains

60 18447
Q:

A contractor undertakes to complete a work in 130 days. He employs 150 men for 25 days and they complete 1/4 of the work . He then reduces the number of men to 100, who work for 60 days, after which there are 10 days holidays.How many men must be employed for the remaining period to finish the work?

Answer

150 men in 25 days do = 14 work  


Let 1 man in 1 day does = x  work  


Total work done by 150 men in 25 days = 150x *  25 = 14   work => x = 115000   


Therefore, 100 men in 60 days do = 100 * 60x = 6000x work = 6/15 = 2/5


Total work done =14 + 25 = 1320 


Therefore, Remaining work = 1 - 1320 = 720  


Remaining time = 130 - (25+60+10) = 35 days 


Therefore, work is done in 25 days by 150 men.


Therefore, Work is done in 35 days by 150 men.


Hence, he should employ 50 more men.

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Subject: Time and Work Exam Prep: Bank Exams , AIEEE
Job Role: Bank PO

47 18441
Q:

The denominator of a fraction is 3 more than the numerator. If the numerator as well as the denominator is increased by 4, the fraction becomes 4/5. What was the original fraction ?

A) 7/11 B) 8/11
C) 9/11 D) 10/11
 
Answer & Explanation Answer: B) 8/11

Explanation:

Let the numerator be x Then, denominator =  x + 3.

Now. (x + 4)/(x + 3) +4 = 4/5  <=> 5 (x + 4) =  4(x + 7)

=>  x = 8.

The fraction is  8/11.

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Filed Under: Problems on Numbers

24 18438
Q:

Find the minimum number of straight lines in the below figure ?

                441484547526.png image

A) 20 B) 19
C) 17 D) 15
 
Answer & Explanation Answer: B) 19

Explanation:

The given figure can be labelled as :

  44-1u1484547679.png image 

Straight lines :

The number of straight lines are 19

i.e. BC, CD, BD, AF, FE, AE, AB, GH, IJ, KL, DE, AG, BH, HI, GJ, IL, JK, KE and DL.

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Filed Under: Analytical Reasoning
Exam Prep: CAT , Bank Exams
Job Role: Bank PO , Bank Clerk

19 18437
Q:

If the C.I. on a sum for 2 years at 12 1/2 % per annum is Rs. 510, the S.I. on the same sum at the same rate for the same period of time is   ?

A) Rs. 580 B) Rs. 480
C) Rs. 550 D) Rs. 470
 
Answer & Explanation Answer: B) Rs. 480

Explanation:

Let the sum be Rs. P. Then,

 

P1+252x1002-P= 510

 

P[982- 1] = 510.

 

Sum = Rs. 1920

 

So, S.I. = (1920 x 25 x 2) / (2 x 100) = Rs. 480

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Filed Under: Simple Interest
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

39 18429