5555+ Aptitude and Reasoning Questions, Answers With Explanation

Q:

Milk and water are mixed in a vessel A as 4:1 and in vessel B as 3:2. For vessel C, if one takes equal quantities from A and B, find the ratio of milk to water in C.

A) 1:9	B) 9:1
C) 3:7	D) 7:3

Answer & Explanation Answer: D) 7:3

Explanation:

Ratio of Milk and water in a vessel A is 4 : 1

Ratio of Milk and water in a vessel B is 3 : 2

Ratio of only milk in vessel A = 4 : 5

Ratio of only milk in vessel B = 3 : 5

Let 'x' be the quantity of milk in vessel C

Now as equal quantities are taken out from both vessels A & B

=> 4/5 : 3/5
x
3/5-x x - 4/5

=> $\frac{\frac{3}{5} - x}{x - \frac{4}{5}}$ = $\frac{1}{1}$ (equal quantities)

=> x = 7/10

Therefore, quantity of milk in vessel C = 7

=> Water quantity = 10 - 7 = 3

Hence the ratio of milk & water in vessel 3 is 7 : 3

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Filed Under: Alligation or Mixture
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

33 17861

Q:

In a certain code language CONCENTRATION is written as QQJGZIGQGDMLX. How will NITRIFICATION be written in that code language?

A) QQJGZXRIKSGRM	B) QQJGYXRIKSGRM
C) QQJGZXRIKSGRN	D) QQJGZRIKSGSM

Answer & Explanation Answer: A) QQJGZXRIKSGRM

Explanation:

The first three letters are coded as same positioned letters from the right end of the alphabet. So are the seventh to tenth letters. The fourth , fifth and sixth letters move one, two and three positions forward respectively in the alphabet. So, do the last three letters. Thus,

CONCENTRATION => XLMDGQGIZGJQQ

Now reverse this and we get QQJGZIGQGDMLX

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Filed Under: Coding and Decoding

79 17856

Q:

If a mirror is placed on the line MN, then which is the right image of the given figure?

A) 1	B) 2
C) 3	D) 4

Answer & Explanation Answer: D) 4

Explanation:

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Filed Under: Image Analysis
Exam Prep: Bank Exams

1 17855

Q:

Select the term missing from the given series?

PG, QH, RI, ?

A) LT	B) ST
C) JK	D) SJ

Answer & Explanation Answer: D) SJ

Explanation:

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Filed Under: Alphabet Test
Exam Prep: Bank Exams

3 17853

Q:

If log 64 = 1.8061, then the value of log 16 will be (approx)?

A) 1.9048	B) 1.2040
C) 0.9840	D) 1.4521

Answer & Explanation Answer: B) 1.2040

Explanation:

Given that, log 64 = 1.8061

i.e $\log (4^{3}) = 1.8061$

--> 3 log 4 = 1.8061

--> log 4 = 0.6020

--> 2 log 4 = 1.2040

$\Rightarrow \log (4^{2}) = 1.2040$

Therefore, log 16 = 1.2040

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Filed Under: Logarithms
Exam Prep: CAT
Job Role: Bank Clerk

50 17846

Q:

Study the following graph carefully and answer the questions given below:

Distribution of candidates who were enrolled for MBA entrance exam and the candidates (out of those enrolled) who passed the exam in different institutes:

1. What percentage of candidates passed the Exam from institute T out of the total number of candidates enrolled from the same institute?

A. 50% B. 62.5% C. 75% D. 80%

2. Which institute has the highest percentage of candidates passed to the candidates enrolled?

A. Q B. R C. V D. T

3. The number of candidates passed from institutes S and P together exceeds the number of candidates enrolled from institutes T and R together by:

A. 228 B. 279 C. 399 D. 407

4. What is the percentage of candidates passed to the candidates enrolled for institutes Q and R together?

A. 68% B. 80% C. 74% D. 65%

5. What is the ratio of candidates passed to the candidates enrolled from institute P?

A. 9:11 B. 14:17 C. 6:11 D. 9:17

Answer

1. ANSWER : C

Explanation - Required percentage= $\frac{9 % o f 5700}{8 % o f 8550} \times 100$ % = $\frac{9 \times 5700}{8 \times 8550} \times 100$ % = 75%

2. ANSWER : B

Explanation - The percentage of candidates passed to candidates enrolled can be determined for each institute as under:

P = $\frac{18 % o f 5700}{22 % o f 8550} \times 100$ % = 54.55%

Q = $\frac{17 % o f 5700}{15 % o f 8550} \times 100$ % = 75.56%

R = $\frac{13 % o f 5700}{10 % o f 8550} \times 100$ % = 86.67%

S = $\frac{16 % o f 5700}{17 % o f 8550} \times 100$ % = 62.75%

T = $\frac{9 % o f 5700}{8 % o f 8550} \times 100$ % = 75%

V= $\frac{15 % o f 5700}{12 % o f 8550} \times 100$ % = 83.33%

X= $\frac{12 % o f 5700}{16 % o f 8550} \times 100$ % = 50%

Highest of these is 86.67% corresponding to institute R.

3. ANSWER : C

Explanation - Required difference = [(16% + 18%) of 5700] - [(8% + 10%) of 8550]

= [(34% of 5700) - (18% of 8550)]

= (1938 - 1539)

= 399

4. ANSWER : B

Explanation - Candidates passed from institutes Q and R together = [(13% + 17%) of 5700] = 30% of 57000.

Candidates enrolled from institutes Q and R together = [(15% + 10%) of 8550] = 25% of 8550.

Required Percentage = $\frac{30 % o f 5700}{25 % o f 8550} \times 100$ % = 80%

5. ANSWER : C

Explanation - Required ratio = $\frac{18 % o f 5700}{22 % o f 8550}$ = 6/11

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Subject: Pie Charts

54 17845

Q:

In the following question, select the missing number from the given series.

64, 75, 86, 97, ?, 119

A) 118	B) 108
C) 98	D) 109

Answer & Explanation Answer: B) 108

Explanation:

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Filed Under: Number Series
Exam Prep: Bank Exams

2 17838

Q:

Which of the following terms follows the trend of the given list?

XYYYYYY, XXYYYYY, XXXYYYY, XXXXYYY, XXXXXYY, _______________.

A) XXXXXXX	B) XYYYYYY
C) XXYYYYY	D) XXXXXXY

Aptitude and Reasoning Questions

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Non Verbal Reasoning

Quantitative Aptitude - Arithmetic Ability

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