Aptitude and Reasoning Questions

Q:

Refer the below data and answer the following question.

What was the revenue of the company if its Expenditure was Rs. 400 crore in the year when its % profit was the least?

A) 210 B) 220
C) 230 D) 200
 
Answer & Explanation Answer: A) 210

Explanation:
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Filed Under: Table Charts
Exam Prep: Bank Exams

0 13239
Q:

If Q means 'add to', J means 'multiply by', T means 'substract from' and K means 'divide by' then 30 K 2 Q 3 J 6 T 5 = ? 

A) 18 B) 28
C) 31 D) 103
 
Answer & Explanation Answer: B) 28

Explanation:

Using Correct Symbols , We have :

Given expression = 30 / 2 + 3 x 6 - 5 = 15 + 18 - 5 = 28

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107 13235
Q:

In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit

A) 70% B) 80%
C) 90% D) None of above
 
Answer & Explanation Answer: A) 70%

Explanation:

Let C.P.= Rs. 100.
Then, Profit = Rs. 320,
S.P. = Rs. 420.

New C.P. = 125% of Rs. 100 = Rs. 125
New S.P. = Rs. 420.

Profit = Rs. (420 - 125) = Rs. 295

Required percentage = (295/420) * 100
= 70%(approx)

 

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Filed Under: Profit and Loss

22 13232
Q:

A can build a wall in 16 days while B can destroy it in 8 days. A worked for 5 days. Then B joined with A for the next 2 days. Find in how many days could A build the remaining wall ?

A) 12 days B) 14 days
C) 13 days D) 16 days
 
Answer & Explanation Answer: C) 13 days

Explanation:

Now, Total work = LCM(16, 8) = 48

A's one day work = + 48/16 = + 3

B's one day work = - 48/8 = -6

Given A worked for 5 days to build the wall => 5 days work = 5 x 3 = + 15

2days B joined with A in working = 2(3 - 6) = - 6

Remaining Work of building wall = 48 - (15 - 6) = 39

Now this remaining work will be done by A in = 39/3 = 13 days.

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Filed Under: Time and Work
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

23 13231
Q:

If a box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains no defective bulbs.

A) 5/12 B) 7/12
C) 3/14 D) 1/12
 
Answer & Explanation Answer: D) 1/12

Explanation:

Total number of elementary events = 10C5

 

Number of ways of selecting no defective bulbs i.e., 5 non-defective bulbs out of 7 is 7C5.

 

So,required probability =7C510C5 = 1/12.

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Filed Under: Probability

20 13231
Q:

What will be compounded amount?
I. Rs. 200 was borrowed for 192 months at 6% compounded annually.
II. Rs. 200 was borrowed for 16 years at 6%.

A) I alone sufficient while II alone not sufficient to answer B) II alone sufficient while I alone not sufficient to answer
C) Either I or II alone sufficient to answer D) Both I and II are not sufficient to answer
 
Answer & Explanation Answer: C) Either I or II alone sufficient to answer

Explanation:

 I. Amount = Rs.200*1+610016

 

II. Amount =Rs200*1+610016

 

Thus, I as well as II gives the answer.

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

2 13230
Q:

If 3x+7=x2+p=7x+5, what is the value of P ?

A) 17/2 B) 25/3
C) 33/4 D) 41/5
 
Answer & Explanation Answer: A) 17/2

Explanation:

 

 

3x+7=7x+5=>7x-3x=2=>4x=2=>x=2

 

Now, 3x+7=x2+p=32+7=14+p=>p=172

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Filed Under: Simplification

11 13221
Q:

Refer the below data table and answer the following question.

What is the average number of children per house?

A) 2.07 B) 1.82
C) 1.57 D) 1.32
 
Answer & Explanation Answer: C) 1.57

Explanation:
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Filed Under: Table Charts
Exam Prep: Bank Exams

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