5555+ Aptitude and Reasoning Questions, Answers With Explanation

Q:

Arrange the following words according to the dictionary order

a. Approach

b. Appropriate

c. Approval

d. Approve

A) acdb	B) abdc
C) cdab	D) abcd

Answer & Explanation Answer: D) abcd

Explanation:

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Filed Under: Verbal Reasoning - Mental Ability

1 4721

Q:

In the following question, select the odd letter/letters from the given alternatives.

A) RMHC	B) XSNI
C) YTOJ	D) ZVQL

Answer & Explanation Answer: D) ZVQL

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

1 4719

Q:

The area of an equilateral triangle is 16√3 sq.cm. Find its side in cm.

A) 8	B) 4
C) 16	D) 24

Answer & Explanation Answer: A) 8

Explanation:

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Filed Under: Area
Exam Prep: Bank Exams

0 4719

Q:

In a certain code language, "who are you" is written as "432", "they is you" is written as "485" and "they are dangerous" is written as "295". How is "dangerous" written in that code language?

A) 2	B) 4
C) 5	D) 9

Answer & Explanation Answer: D) 9

Explanation:

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Filed Under: Coding and Decoding
Exam Prep: Bank Exams

8 4718

Q:

Rice worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, then the price of third variety of rice per kg?

A) Rs. 571.25	B) Rs. 175.5
C) Rs. 751.75	D) Rs. 850

Answer & Explanation Answer: B) Rs. 175.5

Explanation:

Let the price of required variety = Rs. P/kg

Then, respective amounts were m kg, m kg and 2m kg

= 126m + 135m + 2pm = 153 x 4m

=> 2p = 351

p = 175.5 / kg

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Filed Under: Ratios and Proportions
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

37 4716

Q:

The following bar graph indicates the production of sugar (in lakh tonnes) by three different sugar companies P, Q and R over years 2009 to 2013.

Production of Sugar by Companies P, Q and R during 2009 - 2013

1. The percentage increase in production of Company Q from the year 2009 to the year 2013 is :

1. 80% 2. 90% 3. 60% 4. 100%

2. The average production over the years 2009 - 2013 was maximum for the Company(ies):

1. Q 2. P 3. R 4. P and R

3. The percentage rise or fall in production of Company Q as compared to the previous year is the maximum in the year :

1. 2011 2. 2010 3. 2013 4. 2012

4. The percentage of production of Company R to Production of Company Q is the maximum in the year

1. 2010 2. 2009 3. 2011 4. None of these

5. The ratio of the average production of Company P during the years 2011 to 2013 to the average production of Company Q for the same period is :

1. 23 : 25 2. 27 : 29 3. 15 : 17 4. 9 : 11

Answer

1. Answer : 4

Explanation : Required Percentage = $\frac{100 - 50}{50} \times 100$ = 100%

2. Answer : 4

Explanation : The average production of P = $\frac{60 + 90 + 50 + 100 + 80}{5}$ = 76

The average production of Q = $\frac{50 + 70 + 70 + 80 + 100}{5}$ = 74

The average production of R = $\frac{70 + 80 + 90 + 70 + 70}{5}$ = 76

Maximum average production = P and R both

3. Answer : 2

Explanation : The percentage rise in 2010 = $\frac{70 - 50}{50} \times 100$ = 40%

The percentage rise in 2011 = $\frac{70 - 70}{70} \times 100$ = 0%

The percentage rise in 2012 = $\frac{80 - 70}{70} \times 100$ = 14.28%

The percentage rise in 2013 = $\frac{100 - 80}{80} \times 100$ =25%

4. Answer : 2

Explanation : The percentage of production of Company R to production of Company Q

in 2009 = $\frac{70}{50} \times 100$ = 140

in 2010 = $\frac{80}{70} \times 100$ = 114.28

in 2011 = $\frac{90}{70} \times 100$ = 128.57

in 2012 = $\frac{70}{80} \times 100$ = 87.5

in 2013 = $\frac{70}{100} \times 100$ = 70

5. Answer : 1

Explanation : Average production of company P during the years 2011 to 2013 = $\frac{50 + 100 + 80}{3}$ = $\frac{230}{3}$

Average production of company Q during the years 2011 to 2013 = $\frac{70 + 80 + 100}{3}$ = $\frac{250}{3}$

Required ratio = 23 : 25

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Subject: Bar Charts

13 4715

Q:

In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by

A) 5.4 m	B) 4.5 m
C) 5 m	D) 6 m

Answer & Explanation Answer: D) 6 m

Explanation:

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Filed Under: Races and Games

3 4714

Q:

The top and bottom of a tower were seen to be at angles of depression 30° and 60° from the top of a hill of height 100 m. Find the height of the tower ?

A) 42.2 mts	B) 33.45 mts
C) 66.6 mts	D) 58.78 mts

Answer & Explanation Answer: C) 66.6 mts

Explanation:

ht1488353450.jpg image

From above diagram
AC represents the hill and DE represents the tower

Given that AC = 100 m

angleXAD = angleADB = 30° (∵ AX || BD )
angleXAE = angleAEC = 60° (∵ AX || CE)

Let DE = h

Then, BC = DE = h, AB = (100-h) (∵ AC=100 and BC = h), BD = CE

tan 60°=AC/CE => √3 = 100/CE =>CE = 100/√3 ----- (1)

tan 30° = AB/BD => 1/√3 = 100−h/BD => BD = 100−h(√3)
∵ BD = CE and Substitute the value of CE from equation 1
100/√3 = 100−h(√3) => h = 66.66 mts

The height of the tower = 66.66 mts.

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Filed Under: Height and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

15 4709

Aptitude and Reasoning Questions

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Non Verbal Reasoning

Quantitative Aptitude - Arithmetic Ability

Quantitative Aptitude - Data Interpretation

Verbal Reasoning - Logical Deduction

Verbal Reasoning - Mental Ability

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