5555+ Aptitude and Reasoning Questions, Answers With Explanation

Q:

A, B, C, D and E are sitting in a row. B is between A and K Who among them is in the middle ?

I. A is left of 13 and right of D.

II.C is at the right end.

A) If the data in statement I alone are sufficient to answer the question	B) If the data in statement II alone are sufficient answer the question
C) If the data either in I or II alone are sufficient to answer the question;	D) If the data in both the statements together are needed.

Answer & Explanation Answer: D) If the data in both the statements together are needed.

Explanation:

Clearly, we have the order : A. a E. From I, we have the order : D, A, B. E.

From II, we get the complete sequence as D, A, B. E, C.

Clearly. B is in the middle. So, both I and II are required.

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Filed Under: Data Sufficiency

2 11536

Q:

Shawn invested one half of his savings in a bond that paid simple interest for 2 years and received Rs.550 as interest. He invested the remaining in a bond that paid compound interest, interest being compounded annually, for the same 2 years at the same rate of interest and received Rs.605 as interest. What was the value of his total savings before investing in thesetwo bonds?

A) Rs.2543	B) Rs.2534
C) Rs.2546	D) Rs.2750

Answer & Explanation Answer: D) Rs.2750

Explanation:

Shawn received an extra amount of (Rs.605 – Rs.550) Rs.55 on his compound interest paying bond as the interest that he received in the first year also earned interest in the second year.

The extra interest earned on the compound interest bond = Rs.55

The interest for the first year =550/2 = Rs.275

Therefore, the rate of interest = $\frac{55}{275} * 100$ = 20% p.a.

20% interest means that Shawn received 20% of the amount he invested in the bonds as interest.

If 20% of his investment in one of the bonds = Rs.275, then his total investment in each of the bonds = $\frac{275}{20} * 100$ = 1375.

As he invested equal sums in both the bonds, his total savings before investing = 2 x 1375 =Rs.2750.

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

12 11534

Q:

Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats ?

A) 1 : 2 : 3	B) 2 : 3 : 4
C) 3: 4 : 5	D) 4 : 5 : 6

Answer & Explanation Answer: B) 2 : 3 : 4

Explanation:

Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8.

Seats for Mathematics, Physics and Biology in a school are 5x, 7x and 8x.

There is a proposal to increase these seats by 40%, 50% and 75% respectively.

Then Seats for Mathematics, Physics and Biology in a school will be

1.4 X 5x, 1.5 X 7x and 1.75 X 8x and

ratio will be 7 : 10.5 : 14 => 2:3:4.

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Filed Under: Ratios and Proportions
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

21 11522

Q:

If a - b = 3, $(a^{2} + b^{2}) = 29$ , find the value of ab.

A) 10	B) 12
C) 15	D) 18

Answer & Explanation Answer: A) 10

Explanation:

2ab= $(a^{2} + b^{2}) - (a^{2} - b^{2})$

29-9=20

=>ab=10

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Filed Under: Simplification

8 11518

Q:

Find the one which does not belong to that group ?

A) 343	B) 2197
C) 1331	D) 121

Answer & Explanation Answer: D) 121

Explanation:

343 = $7^{3}$ , 1331 = $11^{3}$ , 2197 = $13^{3}$ , 121 = $11^{2}$

343, 1331, 2197 are perfect cubes, but not 121.

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Filed Under: Odd Man Out
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

12 11509

Q:

Refer the below data table and answer the following question.

What percent students who chose engineering are girls?

A) 40	B) 22.86
C) 50	D) 100

Answer & Explanation Answer: C) 50

Explanation:

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Filed Under: Table Charts
Exam Prep: Bank Exams

0 11507

Q:

How many alphabets need to be there in a language if one were to make 1 million distinct 3 digit initials using the alphabets of the language?

A) 1000	B) 100
C) 500	D) 999

Answer & Explanation Answer: B) 100

Explanation:

1 million distinct 3 digit initials are needed.

Let the number of required alphabets in the language be ‘n’.

Therefore, using ‘n’ alphabets we can form n * n * n = $n^{3}$ distinct 3 digit initials.

Note distinct initials is different from initials where the digits are different.

For instance, AAA and BBB are acceptable combinations in the case of distinct initials while they are not permitted when the digits of the initials need to be different.

This $n^{3}$ different initials = 1 million

i.e. $n^{3} = 10^{6}$ (1 million = $10^{6}$ )

=> n = $10^{2}$ = 100

Hence, the language needs to have a minimum of 100 alphabets to achieve the objective.

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Filed Under: Permutations and Combinations

7 11506

Q:

Refer the below data table and answer the following question.

How many students have scored marks 20 or more but less than 40?

A) 44	B) 61
C) 36	D) 105

Aptitude and Reasoning Questions

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Non Verbal Reasoning

Quantitative Aptitude - Arithmetic Ability

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Verbal Reasoning - Logical Deduction

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