Aptitude and Reasoning Questions

Q:

Joel introduces Mary as the daughter of the only son of my father’s wife. How is Joel related to Mary ?

A) Daughter B) Brother
C) Son D) Father
 
Answer & Explanation Answer: D) Father

Explanation:

Resolving from the last , In the view of joel,
My father’s wife – mother
Only son of mother – himself i.e. joel
Daughter of john– daughter.

So Joel is Father of Mary.

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Filed Under: Blood Relations
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29 12556
Q:

Water flows into a tank which is 200 m long and 150 m wide, through a pipe of cross-section (0.3m x 0.2m) at 20 km/h. In what time will the water level be 12m  ?

A) 200 hrs B) 240 hrs
C) 300 hrs D) 270 hrs
 
Answer & Explanation Answer: C) 300 hrs

Explanation:

Volume of water collected in the tank in 1 hour

⇒ (0.3 × 0.2 × 20km × 1000mts) = 1200 m cubic

If after t hours, the water is at height of 12m,

1200t=200×150×12 

⇒ t = 300 Hours.

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Filed Under: Pipes and Cistern
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25 12553
Q:

8 years ago there were 5 members in the Arthur's family and then the average age of the family  was 36 years. Mean while Arthur got married and gave birth to a child. Still the average age of his family is same now. What is the age of his wife at the time of his child's birth was.If the difference between the age of her  child and herself was 26 years.

A) 25 years B) 26 years
C) 20 years D) can't be determined
 
Answer & Explanation Answer: B) 26 years

Explanation:

Since we know that the difference b/w the age of any two persons remains always constant, while the ratio of their ages gets changed as the time changes.

 

so, if the age of his child be x (presently)

 

Then the age of  wife be x + 26 (presently)

 

Thus the total age = x + ( x + 26) = 32  [252-220 =32]

=> x = 3

Therefore, The age of her child is 3 years and her self  is 29 years. Hence her age at the time of the birth of her child was 26 years.

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Filed Under: Average

12 12547
Q:

At an examination in which maximum marks are 500. P got 10% less than Q, Q got 25% more than R and R got 20% less than S. If P got 360 marks what percentage of marks was obtained by S ?

A) 77 B) 74
C) 80 D) 83
 
Answer & Explanation Answer: C) 80

Explanation:

Let marks obtained by S = M

R's marks = 0.80M

Q's marks = 1.25 (0.80M)

P's marks = (0.90) (1.25) (0.80M)

= 0.9M

But 0.9M = 360

M = ?

M = 400

Hence % of marks obtained by S

= 400/500 x 100 = 80%.

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Filed Under: Percentage
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11 12538
Q:

38% of 7500 +  ?% of 375 = 50% of 6000

A) 50 B) 40
C) 60 D) 45
 
Answer & Explanation Answer: B) 40

Explanation:

Let ? = p

38 x 7500/100  + p x 375/100 = 50 x 6000/100

=> 38 x 75 + 3.75p = 3000

=> 3.75p = 3000 - 2850

=> p = 150/3.75 

=> p = ? = 40

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Filed Under: Simplification
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13 12530
Q:

The area of a field in the shape of a trapezium measures 1440sq m. The perpendicular distance between its parallel sides is 24cm. If the ratio of the sides is 5:3, the length of the longer parallel side is:

A) 75 B) 85
C) 95 D) 105
 
Answer & Explanation Answer: A) 75

Explanation:

Area of field = 12*5x+3x*24 = 96x sq.m  

96x = 1440       => x =144096 = 15  

Hence, the length of longer parallel side = 5x = 75m

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

7 12511
Q:

Ashwin fires two bullets from the same place at an interval of 15 minutes but Rahul sitting in a bus approaching the place hears the second sound 14 minutes 30 seconds after the first. If sound travels at the speed of 330 meter per second, what is the approximate speed of bus?

A) 330/29 m/s B) 330 x 30 m/s
C) 330/14 m/s D) 330/900 m/s
 
Answer & Explanation Answer: A) 330/29 m/s

Explanation:

Second gun shot take 30 sec to reach rahul imples distance between two.

given speed of sound = 330 m/s

Now, distance = 330 m/s x 30 sec 

 

Hence, speed of the bus = d/t = 330x30/(14x60 + 30) = 330/29 m/s.

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24 12510
Q:

A trader marked the price of the T.V. 30% above the cost price of the T.V. and gave the purchaser 10% discount on the marked price, thereby gaining Rs.340. Find the cost price of the T.V ?

A) Rs. 2000 B) Rs. 1600
C) Rs. 2200 D) Rs. 2100
 
Answer & Explanation Answer: A) Rs. 2000

Explanation:

Let 'x' be the cost price.
Now Marked price = x + 30x/100 = 13x/10
10% discount = 10/100 x 13x/10 = 13x/100
Selling price = 13x/10 - 13x/100 = 117x/100
Given gain = 340
Here gain = 117x/100 - x = 17x/100 = 340 => x = Rs. 2000.

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Filed Under: Profit and Loss
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13 12508