Aptitude and Reasoning Questions

Q:

Find: S.l. on Rs 3000 at 18% per annum for the period from 4th

A) 118 B) 105
C) 108 D) 110
 
Answer & Explanation Answer: C) 108

Explanation:

(24 + 31 + 18) days = 73 days = 1/5 year .

 

P = Rs 3000 and R = 18 % p.a.

 S.I=3000*18*15100

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Filed Under: Simple Interest
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22 9704
Q:

If 6 men and 3 boys working together, can do four times as much work per hour as a man and a boy together. Find the ratio of the work done by a man and that of a boy for a given time  ?

A) 1 : 2 B) 2 : 1
C) 3 : 1 D) 1 : 3
 
Answer & Explanation Answer: A) 1 : 2

Explanation:

6M + 3B = 4(1M + 1B)
6M + 3B = 4M + 4B
2M = 1B

M/B = 1/2

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Filed Under: Ratios and Proportions
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19 9700
Q:

Rearrange the following sentences (A), (B), (C), (D), (E) and (F) in the proper sequence to form a meaningful paragraph.

(A) It causes a lot of physical problems especially for our eyes, body and mind.
(B) Such a lifestyle makes man lazy and excessively dependent on machines.
(C) Innovative products such as computers, laptops, mobile phones,
(D) Harmful radiation causes various terminal diseases.
(E) Technology has advanced rapidly and man cannot seem to live without it now.
(F) iPads have made things easier for us, but it also has its disadvantages.

Which of the following options is the correct arrangement ?

 

A) E C B A D F B) E C F A D B
C) D C B A E F D) D E B A C F
 
Answer & Explanation Answer: B) E C F A D B

Explanation:
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Filed Under: Logical Sequence of Words
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25 9694
Q:

A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is 

A) 30 B) 36
C) 40 D) 42
 
Answer & Explanation Answer: C) 40

Explanation:

Let distance = x km and usual rate = y kmph.
Then, x/y - x/(y+3) = 40/60 --> 2y (y+3) = 9x ----- (i)
Also, x/(y-2) - x/y = 40/60 --> y(y-2) = 3x -------- (ii)
On dividing (i) by (ii), we get:

x = 40 km.

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Filed Under: Time and Distance
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12 9682
Q:

A jogger is running at 9 kmph alongside a railway track is 240 meters ahead of the engine of a 120 meters long train running at 45 kmph in the same direction. In how much time will the train  pass the jogger ?

A) 48 sec B) 36 sec
C) 18 sec D) 72 sec
 
Answer & Explanation Answer: B) 36 sec

Explanation:

Speed of the train relative to jogger = (45-9) km/hr = 36 km/hr =(36*5/18) m/sec  = 10 m/sec

Distance to be covered =(240 + 120)m = 360 m

 Time taken = 360/10 sec = 36 sec

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Filed Under: Problems on Trains

11 9664
Q:

The interest on Rs.750 for 2yrs is the same as the True Discount on Rs.960 due 2yrs hence . If the rate of interest is same in both cases,it is:

A) 12% B) 14%
C) 15% D) 16
 
Answer & Explanation Answer: B) 14%

Explanation:

S.I on Rs.750= T.D on Rs. 960 

This means P.W of Rs. 960 due 2 years hence is Rs.750 

Therefore , T.D= Rs. (960 - 750) = Rs. 210 

Thus, S.I on Rs. 750 for 2 years is Rs. 210 

Rate =[ (100 x 210) / (750 x 2) ] % = 14%

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Filed Under: True Discount

1 9662
Q:

Rajan's present age is three times his daughter's and nine-thirteenth of his mother's present age. The sum of the present ages of all three of them is 125 years. What is the difference between the present ages of Rajan's daughter and Rajan's mather ?

A) 32 years B) 48 years
C) 62 years D) 50 years
 
Answer & Explanation Answer: D) 50 years

Explanation:

Let Rajan's present age be 'x' years.
=> Then his daughter's present age is = x/3 years.
His mother's present age = 13x/9 years
Now, according to the question,
x + x/3 + 13x/9 = 125
=> x = 125x9/25 = 45
Therefore, required difference = 13x/9 - x/3 = 13x - 3x/9 = 10x/9
=> 10 x 45/9 = 50 years.

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Filed Under: Problems on Ages
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10 9658
Q:

Two vessel P and Q contain milk and water in ratio 3 : 2 and 5 : 3 respectively. If 10 liters of the mixture is removed from vessels P and poured in vessel Q then ratio of milk to water in vessel Q becomes 8 : 5. Find the initial quantity of water in vessel Q.

A) 10 lit B) 6 lit
C) 16 lit D) 12 lit
 
Answer & Explanation Answer: A) 10 lit

Explanation:

Given ratio of initial mixture of milk and water in Q = 5 : 3

Let the initial quantity of mixture in vessel Q = 8x

Let quantity of Milk = 5x and

Let quantity of water = 3x

According to the question,

5x + 10 x 353x + 10 x 25  = 85

=> 25x + 30 = 24x + 32

=> x = 2

Required Initial quantity of milk = 5x = 5 x 2 = 10 lit.

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Filed Under: Ratios and Proportions
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18 9657