Aptitude and Reasoning Questions

Neelam's father is Deepak. Deepika's mother is` Rekha. Deepak is the third child of Ramlal. 

So, Deepak's younger sister Rekha is the daughter of Ramlal. So. Ramlal is father of Rekha and grandfather of her daughter Deepika. 

Assume the family has X girls and Y boys, according to the question,
we can have 2 equations:
X-1=Y, 2(Y-2)=X.
Solve the equations, we get X=4, Y=3.

Second denotes the purpose for which the first is used .

A's spending 90%                 saving = 10%

B's spending 75%                 saving = 25%

C's spending 60%                 saving = 40%

Let us suppose A, B and C saves Rs. 3.5 and 6 respectively.

 10% of A's saving = Rs.3

100% of A's saving =  = Rs. 30

25% of B's saving = Rs. 5

100% of B's saving =  = Rs. 20

40% of C's saving = Rs.6

100% of C's saving =  = Rs. 15

Divide Rs. 6500 in the ratio of 30 : 20 : 15 as

A's Share  =   = Rs. 3000

B's Share   =  = Rs. 2000

C's Share  =  = Rs. 1500

Let the present ages of Arun and Harish be 4x and 3x years respectively.

Then, 4x + 6 = 26 => x = 5

Harish's age = 3x = 15 years.

Speed =[ 78 x ( 5/18 ) ] m/sec = 65/3 m/sec.

Time = 1 minute = 60 sec.

Let the length of the tunnel be x metres.

Then, [ (800 + x )/ 60 ]= 65/3

3(800 + x) = 3900

 x = 500.

A > C  -----(i),   B > D  -----(ii),  E < B  --------(iii),  E > C  ---------(iv),  C > D  ---------(v)

from (i) and (v),   we get    A > C > D   ---------(I)

from (iii) and (iv), we get    B > E > C    --------(II)

From (I) and (II) , it is clear that 'D' is the thinnest.

Let the length of the stationary train Y be LY
Given that length of train X, LX = 300 m
Let the speed of Train X be V.
Since the train X crosses train Y and a pole in 60 seconds and 25 seconds respectively.
=> 300/V = 25 ---> ( 1 )
(300 + LY) / V = 60 ---> ( 2 )
From (1) V = 300/25 = 12 m/sec.
From (2) (300 + LY)/12 = 60
=> 300 + LY = 60 (12) = 720
=> LY = 720 - 300 = 420 m
Length of the stationary train = 420 m