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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

Fumble is to Finesse as Malign is to

A) Slander B) Extol
C) Criticize D) Assurance
 
Answer & Explanation Answer: B) Extol

Explanation:

Fumble means grope, mishandle, drop, mistake, blunder, bungle.

Finesse means skill, grace, elegance, assurance, diplomacy, discretion.

So, they are opposites.

 

Similarly,

Malign means slander or criticize.

Extol means being kind or good-natured. A person without finesse often fumbles. A person without extol in his heart often maligns.

Extol means praise or exalt, benevolence

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Filed Under: Analogy
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE , TOEFL
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136 57155
Q:

Find the odd man out?

3, 12, 39, 120, 364

A) 364 B) 120
C) 39 D) 3
 
Answer & Explanation Answer: A) 364

Explanation:

The given number series is 3, 12, 39, 120, 364

33 + 32 = 3 + 9 = 1212 + 33 = 12 + 27 = 3939 + 34 = 39 + 81 = 120120 + 35 = 120 + 243 = 363 (Not 364)

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Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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7 57070
Q:

Find the odd man out of the following number sequence?

100, 101, 97, 105, 90

A) 90 B) 105
C) 97 D) 101
 
Answer & Explanation Answer: B) 105

Explanation:

The given number series 100, 101, 97, 105, 90

100

100 + 1^2 = 101

101 - 2^2 = 97

97 + 3^2 = 106 ( not 105)

106 - 4^2 = 90

 

Hence, the odd man in the given series is 105.

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Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT
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1 56962
Q:

Find the next number in the given number series?

0, 3, 8, 15, 24, ?

A) 35 B) 37
C) 34 D) 36
 
Answer & Explanation Answer: A) 35

Explanation:

Here the given number series is 0, 3, 8, 15, 24, ?

The next number in the given series can be found such a way that the number series follows a pattern,

22 - 4 = 032 - 6 = 342  - 8 = 852 - 10 = 1562 - 12 = 2472 - 14 = 35Hence, the next number in the iven series is 35.

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Filed Under: Odd Man Out
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3 56743
Q:

What is the area of this trapezoidal garden? (All measurements are in cm)

 

A) 60 sq.cm B) 180 sq.cm
C) 210 sq.cm D) 240 sq.cm
 
Answer & Explanation Answer: D) 240 sq.cm

Explanation:
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Filed Under: Area
Exam Prep: Bank Exams

16 56697
Q:

Suppose 0 < θ < 90, then for every θ 4 sin2 θ + 1 is greater than or equal to ?

 

A) 2 B) 4 sin θ 
C) 4 cos θ  D) 4 tan θ
 
Answer & Explanation Answer: B) 4 sin θ 

Explanation:
We know that,
Arithmetic mean ≥ Geometric mean
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Filed Under: Simplification
Exam Prep: Bank Exams

6 56620
Q:

How many kilograms of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per Kg so that there may be a gain of 10 % by selling the mixture at Rs. 9.24 per Kg ?

A) 36 Kg B) 42 Kg
C) 54 Kg D) 63 Kg
 
Answer & Explanation Answer: D) 63 Kg

Explanation:

By the rule of alligation:


C.P. of 1 kg sugar of 1st kind      C.P. of 1 kg sugar of 2nd kind 

 

  

 

Therefore, Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3. 

Let x kg of sugar of 1st kind be mixed with 27 kg of 2nd kind. 

Then, 7 : 3 = x : 27 or x = (7 x 27 / 3) = 63 kg.

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Filed Under: Alligation or Mixture

147 56619
Q:

From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings?

A) 1/15 B) 1/221
C) 25/57 D) 35/256
 
Answer & Explanation Answer: B) 1/221

Explanation:

 Let S be the sample space

 

Then, n(S) = 52C2= 1326.

 

Let E = event of getting 2 kings out of 4.

 

n(E)  = 52*512*1= 6.

 4C2

=>4*32*1

P(E)=n(E)n(S)=61326=1221

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Filed Under: Probability

44 56510