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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

The area of a square is 49 mm. What is the length of each side?

A) 5mm B) 6mm
C) 7mm D) 8mm
 
Answer & Explanation Answer: C) 7mm

Explanation:

A=S2

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

1 8039
Q:

Find the missing number in series 1 4 27

A) 125 B) 625
C) 404 D) 256
 
Answer & Explanation Answer: D) 256

Explanation:

It follows the rule that

 

1

 

2x2  

 

3x3x3  

 

4x4x4x4  

 

5x5x5x5x5 

 

So the missing number is 4x4x4x4 = 256.

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Filed Under: Number Series
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

21 8037
Q:

Study the bar chart and answer the questions based on it.

 

Production of Pesticides by Coromandal International Ltd. Company (in 1000 tonnes)

 

 

The average production of 1996 and 1997 was exactly equal to the average production of which of the following pairs of years?

A) 2000 and 2001 B) 1999 and 2000
C) 1998 and 2000 D) 1995 and 2001
 
Answer & Explanation Answer: D) 1995 and 2001

Explanation:
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Filed Under: Bar Charts
Exam Prep: Bank Exams

0 8033
Q:

934+7217-9115=?

A) 7 + 719/1020 B) 9 + 817/1020
C) 9 + 719/1020 D) 7 + 817/1020
 
Answer & Explanation Answer: D) 7 + 817/1020

Explanation:

given sum =9+34+7+217-9+115

 

9+7+9+34+217-115

 

=> 7+765+120-681020=>7+8171020 

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Filed Under: Numbers

4 8029
Q:

A train covered k km at 40 kmph and another 2k km at 20 kmph. Find the average speed of the train in covering the entire 3k km ?

A) 28 kmph B) 24 kmph
C) 26 kmph D) 32 kmph
 
Answer & Explanation Answer: B) 24 kmph

Explanation:

Total time taken = k/40 + 2k/20 hours

= 5k/40 = k/8 hours

Average speed = 3k/(k/8) = 24 kmph.

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

6 8026
Q:

The last day of a century cannot be

A) Monday B) Wednesday
C) Tuesday D) Friday
 
Answer & Explanation Answer: C) Tuesday

Explanation:

ke

 

A century means 100 years => 76 normal years and 24 leap years

We know that, a normal year contain 1 odd day (365/7 = 52 weeks + 1 odd day)

a leap year contain 2 odd days (365/7 = 52 weeks + 2 odd days)

100 years => 76 x 1 + 24 x 2 = 124 odd days = 124/7 = (17 weeks + 5 odd days)

200 years => 2 x 5 = 10 = 1 week + 3 odd days

300 years => 3 x 5 = 15 = 2 weeks + 1 odd day

400 years => 4 x 5 = 20 + 1 odd day (leap year) = 3 weeks + 0 odd days

500 years => 5 x 5 = 25+1 = 26/7 = 3 weeks + 5 odd days 

Again repeats...

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Filed Under: Calendar

6 8023
Q:

A train 900 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is ?

A) 400 m B) 300 m
C) 500 m D) 600 m
 
Answer & Explanation Answer: A) 400 m

Explanation:

Speed = 78 x 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (900 + x)/60 = 65/3
x = 400 m.

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

7 8020
Q:

P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ?

A) 99 B) 100
C) 89 D) 1
 
Answer & Explanation Answer: A) 99

Explanation:

Let, Distance between A and B = d

 

Distance travelled by P while it meets Q = d + 11

 

Distance travelled by Q while it meets P = d – 11

 

Distance travelled by Q while it meets R = d + 9

 

Distance travelled by R while it meets Q = d – 9

 

Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11

 

The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9

 

But given Ratio of speeds of P & R => P : R = 3 : 2

 SPSR = SPSQxSQSR = d+11d+9d-11d-9

 

=> d+11d+9d-11d-9 = 3/2

 

=>  d = 1, 99

 

=> d = 99 satisfies.

 

Therefore, Distance between A and B = 99

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Filed Under: Time and Distance
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

16 8014