Sawaal
  • Home/
  • Aptitude and Reasoning

Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

Excluding the stoppages, the speed of a bus is 64 km/hr and including the stoppages the speed o the bus is 48km/hr. For how many minutes does the bus stop per hour?

A) 12.5 minutes B) 15 minutes
C) 10 minutes D) 18 minutes
 
Answer & Explanation Answer: B) 15 minutes

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

37 7179
Q:

Identify the diagram that best represents the relationship among the given classes.

 

Sports, Football, Baseball

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: C) 3

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Logical Venn Diagram
Exam Prep: Bank Exams

1 7177
Q:

A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

A) 2.91 m B) 3 m
C) 5.82 m D) None of these
 
Answer & Explanation Answer: B) 3 m

Explanation:

Area of the park = (60 x 40) = 2400 sq.m  

Area of the lawn = 2109  sq.m 

Area of the crossroads = (2400 - 2109) = 291 sq.m   

 

Let the width of the road be x metres. Then,   

60x + 40x - (x * x) = 291  

=>(x * x) - 100x + 291 = 0    

=>(x - 97)(x - 3) = 0  

=>x=3

Report Error

View Answer Report Error Discuss

Filed Under: Volume and Surface Area

1 7172
Q:

Out of three numbers, the first is twice the second and is half of the third. If the average of the three numbers is 56, what will be the sum of the highest number and the lowest number?

A) 120 B) 160
C) 80 D) 60
 
Answer & Explanation Answer: A) 120

Explanation:

Let the three numbers be x, y, z.

From the gien data,

x = 2y ....(1)

x = z/2 => z = 2(2y) = 4y .....(From 1)  ...........(2)

Given average of three numbers = 56

Then,

 

x + y + z3 = 562y + y + 4y3 = 56  (From 1 & 2)7y = 56 x 3y = 24

Now,

x = 2y => x = 2 x 24 = 48

z = 4y = 4 x 24 = 96

 

Now, the highest number is z = 96 & smallest number is y = 24

 

Hence, required sum of highest number and smallest number

= z + y

= 96 + 24

= 120.

Report Error

View Answer Report Error Discuss

Filed Under: Average
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

15 7169
Q:

What was the day of the week on 28th May, 2006?

A) Thrusday B) Friday
C) Saturday D) Sunday
 
Answer & Explanation Answer: D) Sunday

Explanation:

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days

Jan. Feb. March April May

(31 + 28 + 31 + 30 + 28 ) = 148 days

148 days = (21 weeks + 1 day) 1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.

Given day is Sunday.

Report Error

View Answer Report Error Discuss

Filed Under: Calendar

8 7169
Q:

Which of the following dances is a solo dance?

A) Yakshagana B) Ottan Thullal
C) Bharathanatyam D) Kuchipudi
 
Answer & Explanation Answer: B) Ottan Thullal

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Quantitative Aptitude - Arithmetic Ability

6 7168
Q:

What value replaces " ? " in the below figure ?

k551483003228.jpg image

A) 4 B) 3
C) 2 D) 1
 
Answer & Explanation Answer: D) 1

Explanation:

Here it follows

 

426-153=2 and  3819-2010 =0

 

In the same way  399-93=1

Report Error

View Answer Report Error Discuss

Filed Under: Inserting The Missing Character
Exam Prep: Bank Exams
Job Role: Bank Clerk

128 7163
Q:

The sides of a right-angled triangle are 12 cm, 16 cm, 20 cm respectively. A new right angle Δ is made by joining the midpoints of all the sides. This process continues for infinite then calculate the sum of the areas of all the triangles so made.

A) 312 sq.cm B) 128 sq.cm
C) 412 sq.cm D) 246 sq.cm
 
Answer & Explanation Answer: B) 128 sq.cm

Explanation:

Area =   SSC Quiz : Quantitative Aptitude | 06 - 01 - 18 = 96

 

Sum of Area =  SSC Quiz : Quantitative Aptitude | 06 - 01 - 18

Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

21 7157