Aptitude and Reasoning Questions

Q:

A certain job was assigned to a group of women to do it in 20 days. But 12 women did not turn up for the job and the remaining did the job in 32 days. The original number of women in the group was?

A) 36 B) 32
C) 22 D) 28
 
Answer & Explanation Answer: B) 32

Explanation:

Let the total women in the group be 'W'

Then according to the given data,

 W x 20 = (W-12) x 32

 => W = 32 

Therefore, the total number of women in the group = 32

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Filed Under: Time and Work
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7 6915
Q:

Represent the 0.000256 in vulgar fraction.

 

A) 4/15625 B) 2/15625
C) 16/15625 D) 8/15625
 
Answer & Explanation Answer: A) 4/15625

Explanation:
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Filed Under: Decimal Fractions
Exam Prep: Bank Exams

4 6911
Q:

The sum of one-half, one-third and one-fourth of a number exceeds the number by 22. The number is

A) 264 B) 284
C) 215 D) 302
 
Answer & Explanation Answer: A) 264

Explanation:

Let the number be 'x'. Then, from given data

x/2 + x/3 + x/4 = x+22
13x/12 = x+22
x = 264

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Filed Under: Problems on Numbers
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4 6903
Q:

Directions:

Four friends Raghu, Rajesh, Ramesh and Ravi complete their Graduation in different number of years. The one who took maximum time took eight years to complete his Graduation while the one who took least time took only three years to complete it.Ravi took more time only than Raghu and completed his Graduation in five years. Ramesh did not take longer time
than Rajesh to complete his Graduation.

Question:

Who took more years to complete his graduation among all ?

A) Ramesh B) Raghu
C) Rajesh D) Ravi
 
Answer & Explanation Answer: C) Rajesh

Explanation:

Rajesh   - 8 years

Ramesh - 6 or 7 years

Ravi      - 5 years

Raghu   - 3 years

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Filed Under: Deriving Conclusions From Passages
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4 6902
Q:

Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is :

A) 83 B) 89
C) 85 D) 79
 
Answer & Explanation Answer: C) 85

Explanation:

Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F of 551 and 1073 = 29;
First number = 551/29 = 19
Third number = 1073/29 = 37.
Required sum = 19 + 29 + 37 = 85.

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Filed Under: Problems on Numbers
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5 6900
Q:

Hydrogen is lighter than Hydrogen .Hydrogen is lighter than helium.Therefore,Oxygen is the heaviest of the three gases

A) False B) Probably false
C) True D) Can't say
 
Answer & Explanation Answer: D) Can't say

Explanation:
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38 6900
Q:

A, B and C started a company where their initial investments was in the ratio of 2:3:4. At the end of 6 months, A invested an amount such that his total capital became equal to B's initial capital investment. If the annual profit of B is Rs. 3000 then what is the total profit of the company ?

A) Rs. 9500 B) Rs. 10600
C) Rs. 7500 D) Rs. 8900
 
Answer & Explanation Answer: A) Rs. 9500

Explanation:

Given initial investments ratio = 2 : 3 : 4

At the end of 6 months, A invested an amount such that his total capital became equal to B's initial capital investment

i.e, upto 6 months A's investment is 2 and after 6 months his invstment is 3 = B's investment

Now, Ratio of investment for one year

=> A : B : C = (2×6 + 3×6) : (3×12) : (4×12)

= 30 : 36 : 48

= 5 : 6 : 8

But given B's profit = 3000

=> 6 ratio = 3000

For total => 19 ratio = Rs. 9500.

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Filed Under: Partnership
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7 6892
Q:

If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to ?

A) 13/125 B) 14/57
C) 11/120 D) 16/41
 
Answer & Explanation Answer: C) 11/120

Explanation:

Let the numbers be a and b.
We know that product of two numbers = Product of their HCF and LCM
Then, a + b = 55 and ab = 5 x 120 = 600.
=> The required sum = (1/a) + (1/b) = (a+b)/ab
=55/600 = 11/120

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Filed Under: HCF and LCM
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23 6890