Sawaal
  • Home/
  • Aptitude and Reasoning

Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

In how many ways the letters of the word OLIVER be arranged so that the vowels in the word always occur in the dictionary order as we move from left to right ?

A) 186 B) 144
C) 136 D) 120
 
Answer & Explanation Answer: D) 120

Explanation:

In given word OLIVER there are 3 vowels E, I & O. These can be arranged in only one way as dictionary order E, I & O.

 

There are 6 letters in thegiven word.

 

First arrange 3 vowels.

 

This can be done in 6C3 ways and that too in only one way.(dictionary order E, I & O)

 

Remaining 3 letters can be placed in 3 places = 3! ways

 

Total number of possible ways of arranging letters of OLIVER = 3! x C36 ways = 6x5x4 = 120 ways.

Report Error

View Answer Report Error Discuss

Filed Under: Permutations and Combinations
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

11 7115
Q:

Course materials are sent to students by a distance teaching institution. The probability that they will send a wrong programme’s study material is 1/5. There is a probability of 3/4 that the package is damaged in transit, and there is a probability of 1/3 that there is a short shipment. What is the probability that the complete material for the course arrives without any damage in transit? 

A) 4/5 B) 2/3
C) 1/2 D) 2/15
 
Answer & Explanation Answer: D) 2/15

Explanation:

Probability of sending the correct material is 4/5

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Probability of the material not being damaged in transit is 1/4

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Probability that there is no short shipment = 2/3

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

∴ Required probability =4/5 x 1/4 x 2/3 = 2/15

Report Error

View Answer Report Error Discuss

Filed Under: Quantitative Aptitude - Arithmetic Ability

2 7112
Q:

What is the difference between the biggest and the smallest fraction among 2/3 , 3/4 , 4/5 and 5/6?

A) 1/6 B) 1/12
C) 1/20 D) 1/30
 
Answer & Explanation Answer: A) 1/6

Explanation:

Converting each of the given fractions into decimal form, we get

2/3 = 0.66, 3/4 = 0.75, 4/5 = 0.8, 5/6 = 0.833 

Since 0.833>0.8>0.75>0.66 

So, 5/6 > 4/5 > 3/4 > 2/3 

Therefore,  Required Difference = 5/6 - 2/3 = 1/6

Report Error

View Answer Report Error Discuss

Filed Under: Decimal Fractions

5 7111
Q:

Four persons are to be choosen from a group of 3 men, 2 women and 4 children. Find the probability of selecting 1 man,1 woman and 2 children.

A) 2/7 B) 3/7
C) 4/7 D) 3/7
 
Answer & Explanation Answer: A) 2/7

Explanation:

Total number of persons = 9

 

Out of 9 persons 4 persons can be selected in 9C4 ways =126

 

1 man,1 woman and 2 children can be selected in 3C1*2C1*4C1 ways =36

So,required probability = 36/126 =2/7

Report Error

View Answer Report Error Discuss

Filed Under: Probability

3 7104
Q:

If Rs.20 is the True Discount on Rs260due after a certain time.What wil be true discount on the same sum due after half of the former time, the rate of interest being the same?

A) Rs.9.40 B) Rs.10.14
C) Rs.10.40 D) Rs.9.14
 
Answer & Explanation Answer: C) Rs.10.40

Explanation:

Simple Interest on Rs. (260-20) for a gven time= Rs.20 

Simple Interest on Rs. (260-20) for a half time  = Rs.10 

True Discount on Rs.250 = Rs.10  

True Discount on Rs.260 = Rs.[(10/250) x 260] = Rs. 10.40

Report Error

View Answer Report Error Discuss

Filed Under: True Discount

2 7104
Q:

Rajitha invested 25% more than Santhosh. Santhosh invested 30% less than Raju, who invested Rs. 6,000. What is the ratio of the amount that Rajitha invested to the total amount invested by all of them together ?

A) 25 : 114 B) 35 : 103
C) 15 : 108 D) 41 : 94
 
Answer & Explanation Answer: B) 35 : 103

Explanation:

Santhosh's investment = 6000 x 70/100 = Rs.4200
Rajitha's investment = 4200 x 5/4 = Rs.5250
Therefore, total amount invested = 6000 + 4200 + 5250 = Rs.15450.
Required ratio = 5250 : 15450 = 35 : 103.

Report Error

View Answer Report Error Discuss

Filed Under: Ratios and Proportions
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

5 7102
Q:

A single pipe of diameter x has to be replaced by six pipes of diameters 12 cm each. The pipes are used to covey some liquid in a laboratory. If the speed/flow of the liquid is maintained the same then the value of x is ?

A) 14.69 cm B) 29.39 cm
C) 18.65 cm D) 22.21 cm
 
Answer & Explanation Answer: B) 29.39 cm

Explanation:

Volume of water flowing through 1 pipe of diameter x = Volume discharged by 6 pipes of diameter 12 cms.

 

As speed is same, area of cross sections should be same. 

 

Area of bigger pipe of diameter x = Total area of 6 smaller pipes of diameter 12 

i.e πR2 = 6πR12   

Here R = R and R1 = 12/2 = 6   

⇒R2 = 6×6×6   

R = 14.696   

=> D = X = 14.696 * 2 = 29.3938 cm.

Report Error

View Answer Report Error Discuss

Filed Under: Volume and Surface Area
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

9 7102
Q:

Man:Machine::Master:?

A) Slave B) Worker
C) Manager D) House
 
Answer & Explanation Answer: A) Slave

Explanation:

A machine is made to work by a man. Similarly, a slave is made to work by a master.

 

Hence, Man:Machine::Master:Slave.

Report Error

View Answer Report Error Discuss

Filed Under: Analogy
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

6 7101