Aptitude and Reasoning Questions

Q:

Out of the five integral numbers C is the average of A and D.  B is greater than C and less than D.Also B is the average of A and E . The middle most number in the sequence 

A) A B) B
C) C D) D
 
Answer & Explanation Answer: B) B

Explanation:

     D _  C  _ A          --------(1)

     D > B > C           --------(2)

from (1) and (2)

     D > B > C > A   ---------(3)

 

Again      E _ B _ A

But B > A, from (3)

So          E > D > B > C > A      [ Since B is the average of E and A so it is eqidistant from both E and A]

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Filed Under: Average

6 7086
Q:

What do you understand by - 'If K is there L has to be there'

A) K & L will always be together B) K is not there, then L will not be there
C) k is there, then L will also be there D) K & L will always be not together
 
Answer & Explanation Answer: C) k is there, then L will also be there

Explanation:

This would not mean that K and L will always be together. It just implies that, if K is there, then L will also be there.

At the same time, it can happen that L is there but K isn't.

Remember, the condition is on K, not on L.

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Filed Under: Analytical Reasoning
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17 7085
Q:

Four subjects — Physics, Chemistry, Mathematics and Biology were taught in four consecutive periods of one hour each starting from 8.00 a.m. At what time was the Chemistry period scheduled ?  

I. Mathematics period ended at 10.00 a.m. which was preceded by Biology. 

II. Physics was scheduled in the last period. 

III. Mathematics period was immediately followed by Chemistry. 

A) Only I B) Only I or Only II
C) Only II D) I and II together or I and III together
 
Answer & Explanation Answer: D) I and II together or I and III together

Explanation:

From I and II. we conclude that Mathematics period began at 9.00 a.m., Biology period began at 8.00 a.m. and Physics period began at 11 a.m. So. the Chemistry period began at 10.00 a.m. From I and III, we conclude that Mathematics period ended and Chemistry period began at 10.00 a.m.  

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Filed Under: Data Sufficiency

5 7084
Q:

At an examination in which maximum marks are 500. K got 10% less than L, L got 25% more than M and M got 20% less than N. If K got 360 marks what percentage of marks was obtained by N ?

A) 80 B) 87
C) 78 D) 76
 
Answer & Explanation Answer: A) 80

Explanation:

Let marks obtained by N = x

M's marks = 0.80x

L's marks = 1.25 (0.80x)

K's marks = (0.90) (1.25) (0.80x)

= 0.9x

But 0.9x = 360 ⇒ x = 400

Percentage of Marks obtained by N

= 400 x 100/500 = 80%

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Filed Under: Percentage
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7 7083
Q:

Determine the exact and ordinary simple interest on a 90-day loan of $8000 at 812 %

A) 150$ B) $160
C) $170 D) $180
 
Answer & Explanation Answer: C) $170

Explanation:

Exact interest, I= prt = $8000 × 0.085 × 90/365 = 167.67

 

Ordinary Interest, I= Prt = $8000 x 0.085 x 90/360 = 170

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Filed Under: Simple Interest
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1 7081
Q:

80% of 900 + 162 x 4 x ? = 113 - 99

A) 0.5 B) 1
C) 4 D) 0
 
Answer & Explanation Answer: A) 0.5

Explanation:

80x900/100 + 256 x 4 x ? = 1331 - 99

720 + 1024 x ? = 1232

? = 1232 - 720/1024

? = 512/1024 = 0.5

? = 0.5 

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Filed Under: Percentage
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11 7073
Q:

Dilatory : Expeditious :: Direct : ?

A) Straight B) Curved
C) Circumlocutory D) Tortuous
 
Answer & Explanation Answer: C) Circumlocutory

Explanation:

The words in each pair are opposites of each other. 

Hence, Dilatory : Expeditious :: Direct : Circumlocutory.

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Filed Under: Analogy
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9 7073
Q:

If the radius of a circle is decreased by 50% , find the percentage decrease in its area.

A) 75% B) 65%
C) 35% D) 25%
 
Answer & Explanation Answer: A) 75%

Explanation:

let original radius = r and  new radius = (50/100) r = r/2

 


original area = πr2 and new area = πr/22

 


decrease in area =  3πr2/4*1πr2 *100 = 75%

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Filed Under: Area
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0 7072