Aptitude and Reasoning Questions

Q:

The value of log3437 is :

A) 1/3 B) -3
C) -1/3 D) 3
 
Answer & Explanation Answer: A) 1/3

Explanation:

log3437log73713log77We know that logxx = 1=> 13

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Filed Under: Logarithms
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12 5422
Q:

What will be added to the unit digits of the number 86236 so that number will be divisible by 9  ?

A) 1 B) 2
C) 3 D) 0
 
Answer & Explanation Answer: B) 2

Explanation:

A number is divisible by 9 only if the sum of the digits of the number is divisible by 9.

Here 86236 = 8 + 6 + 2 + 3 + 6 = 25

We must add 2 to 25 to become 27 which is divisible by 9.

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Filed Under: Problems on Numbers
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4 5420
Q:

Virus doubles every 3 mins. It is 'K' in 1 hour, when was it K/4 ?

A) 29 min B) 25 min
C) 54 min D) 57 min
 
Answer & Explanation Answer: C) 54 min

Explanation:

If virus is K in 1hr i.e 60 min
then in 57 min it was K/2 as it doubles every 3 minutes
=> In 54 min it was K/4.
At 54 minutes it was K/4.

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Filed Under: Arithmetical Reasoning
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6 5418
Q:

M, N and O can complete the work in 18, 36 and 54 days respectively. M started the work and worked for 8 days, then N and O joined him and they all worked together for some days. M left the job one day before completion of work. For how many days they all worked together?

A) 4 B) 5
C) 3 D) 6
 
Answer & Explanation Answer: B) 5

Explanation:

Let M, N and O worked together for x days.

From the given data,
M alone worked for 8 days
M,N,O worked for x days
N, O worked for 1 day

But given that
M alone can complete the work in 18 days
N alone can complete the work in 36 days
O alone can complete the work in 54 days

The total work can be the LCM of 18, 6, 54 = 108 units

M's 1 day work = 108/18 = 6 units
N's 1 day work = 108/36 = 3 units
O's 1 day work = 108/54 = 2 units

Now, the equation is
8 x 6 + 11x + 5 x 1 = 108
48 + 11x + 5 = 108
11x = 103 - 48
11x = 55
x = 5 days.

Hence, all M,N and O together worked for 5 days.

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Filed Under: Time and Work
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3 5417
Q:

From a deck of 52 cards, a 5 card hand is dealt.How many distinct hands can be formed if there are atleast 2 queens?

A) 103336 B) 120000
C) 108336 D) 108333
 
Answer & Explanation Answer: C) 108336

Explanation:

The total possible cases would be a 5 card hand with no restrictions :52C5 5

 

The unwanted cases are:

 

no queens(out of 48 non-queens cards we get 5) 48C5

 

only 1 queen(out of 4 queens we get 1,and out of 48 non-queens we get 4) 4C1*48C4

 

Therefore,52C5-(48C5+4C1*48C4) = 108336

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2 5414
Q:

In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by

A) 5.4 m B) 4.5 m
C) 5 m D) 6 m
 
Answer & Explanation Answer: D) 6 m

Explanation:

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Filed Under: Races and Games

3 5414
Q:

In the following question, a matrix of certain characters is given.These characters follow a certain trend, row-wise or column wise.Find out this trend and choose the missing character accordingly

11 6 8
17 12 ?
25 34 19
19 28 11

A) 16 B) 15
C) 13 D) 9
 
Answer & Explanation Answer: A) 16

Explanation:

 

In the first column, 17 - 11 = 25 - 19 = 6.
In the second column, 12 - 6 = 34 - 28 = 6.
Let the missing number in the third column be y.
Then, y - 8 = 19 - 11 = 8 or y = 16.

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167 5412
Q:

A cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:

A) 49 sq.m B) 50 sq.m
C) 51 sq.m D) 52 sq.m
 
Answer & Explanation Answer: A) 49 sq.m

Explanation:

ke

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