Aptitude and Reasoning Questions

Q:

Compute of 1848 / 231 - 10 = ?

 

A) 2 B) -2
C) 188/221 D) 1884/221
 
Answer & Explanation Answer: B) -2

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

2 55458
Q:

The ratio of two numbers is 3 : 4 and their H.C.F is 4. Their L.C.M is 

A) 12 B) 16
C) 24 D) 48
 
Answer & Explanation Answer: D) 48

Explanation:

Let the numbers be  3x and 4x . Then their H.C.F = x. So, x=4

 Therefore, The numbers are 12 and 16

 L.C.M of 12 and 16 = 48

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Filed Under: HCF and LCM

127 55436
Q:

Complete the series

A, B, D, G,?, P

A) I B) J
C) K D) L
 
Answer & Explanation Answer: C) K

Explanation:

A + 1→B + 2→D + 3→G +4→K +5→P

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Filed Under: Alphabet Test
Exam Prep: Bank Exams

6 55420
Q:

Find the odd word/letters/number pair from the given alternatives.

(A) 16-28

(B) 20-30

(C) 30-40

(D) 40-50

A) A B) B
C) C D) D
 
Answer & Explanation Answer: A) A

Explanation:
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Filed Under: Odd Man Out
Exam Prep: Bank Exams

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Q:

Find the next number in the number series?

1, 4, 12, 32, ?

A) 80 B) 100
C) 192 D) 169
 
Answer & Explanation Answer: A) 80

Explanation:

Next number of the sequence 1, 4, 12, 32,...

1 = 2 x 20

4 = 2 x 21

12 = 3 x 22

32 = 4 x 23

80 = 5 x 24.

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Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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5 55327
Q:

If (3/2)X = (5/7)Y = (6/5)Z, then what is X : Y : Z?

 

A) 105 : 50 : 84 B) 24 : 25 : 32
C) 15 : 21 : 25 D) 20 : 42 : 25
 
Answer & Explanation Answer: D) 20 : 42 : 25

Explanation:
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Filed Under: Ratios and Proportions
Exam Prep: Bank Exams

20 55239
Q:

Find the odd man out of the number series?

18, 37, 76, 155, 314, 635

A) 37 B) 155
C) 314 D) 635
 
Answer & Explanation Answer: D) 635

Explanation:

Given Number series is 18     37     76     155     314     635

 

follows a pattern that, 

 

18

 

18 x 2 +1 = 37

 

37 x 2 +2 = 76

 

76 x 2 +3 = 155

 

155 x 2 +4 = 314

 

314 x 2 +5 = 633 not 635

 

 

 

Hence, the odd man is 635.

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Filed Under: Odd Man Out
Exam Prep: GATE , CAT , Bank Exams , AIEEE
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7 55237
Q:

What is the compound interest earned at the end of 3 years?

I. Simple interest earned on that amount at the same rate and for the same period is Rs. 4500.

II.The rate of interest is 10 p.c.p.a.

III.Compound interest for 3 years is more than the simple interest for that period by Rs.465.

A) I and II only B) II and III only
C) I and III only D) Either II or III only
 
Answer & Explanation Answer: D) Either II or III only

Explanation:

 

 

 

 

 

 

I. gives, S.I for 3 years = Rs. 4500.

 

 

 

II. gives, Rate = 10% p.a.

 

 

 

III. gives, (C.I.) - (S.I.) = Rs. 465.

 

 

 

Clearly, using I and III we get C.I. = Rs. (465 + 4500).

 

 

 

Thus, II is redundant.

 

 

 

Also, from I and II, we get sum =

 

 

 

100 x 4500

 

 

 

= 15000.

 

 

 

10 x 3

 

 

 

Now C.I. on Rs. 15000 at 10% p.a. for 3 years may be obtained.

 

 

 

Thus, III is redundant.

 

 

 

Either II or III is redundant.

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