Aptitude and Reasoning Questions

Q:

Looking at a portrait of a man, Akhil said, "His mother is the wife of my father's son. Brothers and sisters I have none." At whose portrait was Akhil looking ?

A) His uncle B) His nephew
C) His cousin D) His son
 
Answer & Explanation Answer: D) His son

Explanation:

Since Akhil has no brother or sister, so he is his father's only son.
So wife of Akhil's father's son---Akhil's wife.
Thus, Akhil's wife is the man's mother or the man is Akhil's son.

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Filed Under: Blood Relations
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8 4849
Q:

Mary is 12 years younger to Pinky. After 3 years, the ratio of their ages will be 5:8. If the present age of Sam is the sum of ages of Mary and Pinky, then what was the age of Sam 15 years back ?

A) 31 years B) 37 years
C) 46 years D) 29 years
 
Answer & Explanation Answer: A) 31 years

Explanation:

Let the present age of Pinky be x years

 

Then the age of Mary is x - 12 years

 

After 3 years,

 

Ratio of  MaryPinky = x - 9x + 3 = 58

 

8x - 72 = 5x +15

 

=> 3x = 87

 

=> x = 29

 

=> Age of Pinky = 29 years

 

=> Age of Mary = 29 - 12 = 17 years

 

Present age of Sam = 29 + 17 = 46

 

Before 15 years Sam age = 46 - 15 = 31 years.

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Filed Under: Problems on Ages
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Q:

A box contains 5 green, 4 yellow and 5 white pearls. Four pearls are drawn at random. What is the probability that they are not of the same colour ?

A)  11/91

B)  4/11

C)  1/11

D) 90/91

A) Option A B) Option B
C) Option C D) Option D
 
Answer & Explanation Answer: D) Option D

Explanation:

Let S be the sample space. Then,
n(s) = number of ways of drawing 4 pearls out of 14


= C414 ways = 14×13×12×114×3×2×1= 1001


Let E be the event of drawing 4 pearls of the same colour.
Then, E = event of drawing (4 pearls out of 5) or (4 pearls out of 4) or (4 pearls out of 5)

  C15+ C44+ C15 = 5+1+5 =11

 P(E) = n(E)n(S)=111001=191  

 

 Required probability = 1-191=9091

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Filed Under: Permutations and Combinations
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8 4846
Q:

How many such pairs of letters are there in the word ELEVATION each of which have as many letters between them in the word as they have between them in the English Alphabet?

A) One B) Two
C) Three D) More than three
 
Answer & Explanation Answer: C) Three

Explanation:
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Filed Under: Verbal Reasoning - Mental Ability
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5 4844
Q:

The value of 13log10125 - 2log104 + log1032 :

A) 0 B) 1
C) 2 D) 4/5
 
Answer & Explanation Answer: B) 1

Explanation:
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Filed Under: Logarithms
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24 4842
Q:

Statements :
All kids are God.
No God is a Human.
Some Human are Son.
All Son are Men.

Conclusions :
(a) Some Son are not God.
(b) Some Men are Human.

A) Only A follows B) Only B follows
C) Both (A) and (B) follows D) Neither (A) nor (B) follows
 
Answer & Explanation Answer: C) Both (A) and (B) follows

Explanation:
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Filed Under: Statement and Conclusions
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8 4840
Q:

 0.204×420.07×3.4 is equal to:

A) 1/6 B) 0.06
C) 0.6 D) 6
 
Answer & Explanation Answer: D) 6

Explanation:

0.204×420.07×3.4=8568238=36 =6

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7 4834
Q:

If A1, A2, A3, A4, ..... A10 are speakers for a meeting and A1 always speaks after, A2 then the number of ways they can speak in the meeting is 

A) 9! B) 9!/2
C) 10! D) 10!/2
 
Answer & Explanation Answer: D) 10!/2

Explanation:

As A1 speaks always after A2, they can speak only in  1st  to 9th places and 

 

A2 can speak in 2nd to 10 the places only when A1 speaks in 1st place 

 

A2 can speak in 9 places the remaining 

 

 A3, A4, A5,...A10  has no restriction. So, they can speak in 9.8! ways. i.e

 

when A2 speaks in the first place, the number of ways they can speak is 9.8!.

 

When A2 speaks in second place, the number of ways they can speak is  8.8!.

 

When A2 speaks in third place, the number of ways they can speak is  7.8!. When A2 speaks in the ninth place, the number of ways they can speak is 1.8!

 

 

 

Therefore,Total Number of ways they can  speak = (9+8+7+6+5+4+3+2+1) 8! = 92(9+1)8! = 10!/2

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Filed Under: Permutations and Combinations
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