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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

A child must have had 

A) Toys B) Friends
C) Parents D) Education
 
Answer & Explanation Answer: C) Parents

Explanation:
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Filed Under: Verification of Truth of the statement

24 4730
Q:

Out of 3 girls and 6 boys a group of three members is to be formed in such a way that at least one member is a girl. In how many different ways can it be done?

A) 64 B) 84
C) 56 D) 20
 
Answer & Explanation Answer: A) 64

Explanation:

Total number of possible ways = 9C3 = 84 ways

Required atleast one girl in the group of three = total possible ways - ways in which none is girl

None of the members in the group is girl = 6C3 = 20

 

Therefore, number of ways that at least one member is a girl in the group of three

= 84 - 20

= 64 ways.

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Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

14 4727
Q:

The effective annual rate of interest corresponding to nominal rate of 6% per annum payable half yearly is

A) 5% B) 6%
C) 7% D) 6.09%
 
Answer & Explanation Answer: D) 6.09%

Explanation:

amount=[100(1+3/100)^2]=Rs.106.09

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

1 4720
Q:

If two painters can complete two rooms in two hours, how many painters would it take to do 18 rooms in 6 hours?

A) 2 painters B) 6 painters
C) 4 painters D) None
 
Answer & Explanation Answer: B) 6 painters

Explanation:

Two painters can complete two rooms in two hours.So 18 rooms can be painted in 6 hrs by 6 painters

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Filed Under: Problems on Numbers

1 4718
Q:

Which of the following cube in the answer figure cannot be made based on the unfolded cube in the question figure?

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: A) 1

Explanation:
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Filed Under: Cubes and Dice
Exam Prep: Bank Exams

3 4717
Q:

The first of April is a Wednesday. What day of the week will it be on the first of May of the same year?

A) Saturday B) Friday
C) Sunday D) Monday
 
Answer & Explanation Answer: B) Friday

Explanation:
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Filed Under: Calendar
Exam Prep: Bank Exams

29 4712
Q:

If two cards are taken one after another without replacing from a pack of 52 cards. What is the probability for the two cards be Ace ?

A) 51/1221 B) 42/221
C) 1/221 D) 52/1245
 
Answer & Explanation Answer: C) 1/221

Explanation:

Total Combination of getting a card from 52 cards = C152

Because there is no replacement, so number of cards after getting first card= 51

Now, Combination of getting an another card= C151


Total combination of getting 2 cards from 52 cards without replacement= (C152×C151) 


There are total 4 Ace in stack. Combination of getting 1 Ace is = C14

 

Because there is no replacement, So number of cards after getting first Ace = 3


Combination of getting an another Ace = C13

Total Combination of getting 2 Ace without replacement=C14×C13

Now,Probability of getting 2 cards which are Ace =C14×C13C152×C151 = 1/221.

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Filed Under: Permutations and Combinations
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

5 4711
Q:

If J is the interest on K and K is the interest on L, the rate and time is the same on both the cases. What is the relation between J, K and L  ?

A) J x J = KL B) K x K= JL
C) L x L = JK D) JKL = 1
 
Answer & Explanation Answer: B) K x K= JL

Explanation:

Let the Time be 'N' and Rate be 'R' 

J = (K x NR)/100 K = (L x NR)/100 

J/K = NR/100 K/L = NR/100 

J/K = K/L 

K x K = JL

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Filed Under: Simple Interest
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

8 4709