Aptitude and Reasoning Questions

Q:

ΔPQR is right angled at Q. If m∠R=300, then find the value of (cosP - 1/3).

 

A) 1/6 B)  (2√2-1)/√2
C)  -1/√3 D)  (√3-4)/2√3
 
Answer & Explanation Answer: A) 1/6

Explanation:
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Filed Under: Area
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1 57251
Q:

Solve : 2x + 4 = x - 3

 

A) 7 B) -7
C) -1 D) 1
 
Answer & Explanation Answer: B) -7

Explanation:
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Filed Under: Simplification
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1 57013
Q:

How many kilograms of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per Kg so that there may be a gain of 10 % by selling the mixture at Rs. 9.24 per Kg ?

A) 36 Kg B) 42 Kg
C) 54 Kg D) 63 Kg
 
Answer & Explanation Answer: D) 63 Kg

Explanation:

By the rule of alligation:


C.P. of 1 kg sugar of 1st kind      C.P. of 1 kg sugar of 2nd kind 

 

  

 

Therefore, Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3. 

Let x kg of sugar of 1st kind be mixed with 27 kg of 2nd kind. 

Then, 7 : 3 = x : 27 or x = (7 x 27 / 3) = 63 kg.

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Filed Under: Alligation or Mixture

147 57006
Q:

What is the value of KL ?

Statement A: K2= 4.
Statement B: L = 0.

A) Only A is sufficient B) Only B is sufficient
C) Both (A) and (B) are sufficient D) None of the above
 
Answer & Explanation Answer: B) Only B is sufficient

Explanation:

From statement B, 

As the value of L = 0, the value of KL = 0.

Hence only statement B is sufficient.

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Filed Under: Statement and Conclusions
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4 56999
Q:

Calculate the area (in cm2) of a circle whose diameter is 7 cm.

 

A) 38.5   B)  77    
C) 32.5   D) 65
 
Answer & Explanation Answer: A) 38.5  

Explanation:
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0 56933
Q:

A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is

A) 35.55 km/hr B) 36 km/hr
C) 71.11 km/hr D) 71 km/hr
 
Answer & Explanation Answer: C) 71.11 km/hr

Explanation:

Total time taken    = (160/64 + 160/8)hrs
                           = 9/2 hrs.


Average speed    = (320 x 2/9) km.hr
                         = 71.11 km/hr.

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Filed Under: Time and Distance

152 56881
Q:

From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings?

A) 1/15 B) 1/221
C) 25/57 D) 35/256
 
Answer & Explanation Answer: B) 1/221

Explanation:

 Let S be the sample space

 

Then, n(S) = 52C2= 1326.

 

Let E = event of getting 2 kings out of 4.

 

n(E)  = 52*512*1= 6.

 4C2

=>4*32*1

P(E)=n(E)n(S)=61326=1221

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Filed Under: Probability

44 56786
Q:

Solve : x - 3 = 3x + 7

 

 

A) 5 B) -5
C) 1 D) 10/4
 
Answer & Explanation Answer: B) -5

Explanation:
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Filed Under: Simplification
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0 56746