Aptitude and Reasoning Questions

Q:

If x = 0.139, then what is the value of  4x2 + 4x + 1 ?

 

A) 1.39 B) 1.278
C) 2.139 D) 1.69
 
Answer & Explanation Answer: B) 1.278

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

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Q:

Use continuity to evaluate the limit.

limx128+x8+x

 

A) 1 B) 2
C) 4 D) 0
 
Answer & Explanation Answer: A) 1

Explanation:

Since, we have that,

The numerator and denominator is (8+x), which is a polynomial is continuous for all the real numbers i.e. for all x belonging to .

Thus, the limit exists and is given by,

limx128+x8+x = 8+128+12= 1.

 

 

 

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Filed Under: Simplification
Exam Prep: Bank Exams , CAT

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Q:

If s + 1s = 4, then the value of s2 + 1s2

 

A) 14 B) 16
C) 20 D) 24
 
Answer & Explanation Answer: A) 14

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Q:

If x2 = 252 - 152, then find the value of x?

 

A) 40 B) 50
C) 20 D) 25
 
Answer & Explanation Answer: C) 20

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Exam Prep: Bank Exams

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Q:

Find the appropriate value of '?' in (14.998)3 = ?

 

A) 3573 B) 4096
C) 3378 D) 3374
 
Answer & Explanation Answer: D) 3374

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Exam Prep: Bank Exams

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Q:

ΔABC is right angled at B. If cotA = 8/15, then what is the value of cosC ?

 

A) 15/8   B) 8/17  
C) 17/15   D) 15/17
 
Answer & Explanation Answer: D) 15/17

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Exam Prep: Bank Exams

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Q:

What annual instalment will discharge a debt of Rs 1092 due in 3 years at 12% simple interest?

A) Rs.325 B) Rs.545
C) Rs.560 D) Rs.550
 
Answer & Explanation Answer: A) Rs.325

Explanation:

Let each instalment be Rs.x .

 

1st year =  [x + (x * 12 * 2)/100] 

2nd year = [ x + (x *12 * 1)/100] 

3rd year = x 

Then, [x + (x * 12 * 2)/100] + [ x + (x *12 * 1)/100] + x =1092 

3x + ( 24x/100 ) + ( 12x/100 )  = 1092 

336x =109200

Therefore, x = 325 

Each instalment = Rs. 325

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Filed Under: Simple Interest
Exam Prep: GRE

206 50461
Q:

What is the simplified form of 64288 ?

 

A) 23 B) 1/2
C) 23 D) 33
 
Answer & Explanation Answer: A) 23

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

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