Aptitude and Reasoning Questions

Q:

A man spends 59% of his income and saves the rest. What percentage of his expenditure does he save?

A) 72.57 percent B) 83.19 percent
C) 89.09 percent D) 69.49 percent
 
Answer & Explanation Answer: D) 69.49 percent

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Q:

Deepak introduces Raju saying, "He is the husband of the granddaughter of the father of my father." How is Raju related to Deepak?

A) Son-in-law B) Brother-in-law
C) Son D) Brother
 
Answer & Explanation Answer: B) Brother-in-law

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Q:

When x2+ax+b is divided by (x-1), the remainder is 15 and when x2+bx+a is divided by (x+1), the remainder is -1, then the value of a2+b2 is

A) 10 B) 20
C) 8 D) 16
 
Answer & Explanation Answer: A) 10

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Q:

A sum of Rs 4000 becomes Rs 6000 in 1 year at a certain rate of compound interest. What will be the sum (in Rs) after 4 years?

A) 16250 B) 12000
C) 20250 D) 19500
 
Answer & Explanation Answer: C) 20250

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Q:

An angle is (2/3)rd of its supplementary angle. What is the measure of the angle?

A) 108° B) 72°
C) 54° D) 36°
 
Answer & Explanation Answer: B) 72°

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Q:

Which of the following cube in the answer figure cannot be made based on the unfolded cube in the question figure?

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: D) 4

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Q:

The average (arithmetic mean) amount of savings of ten students is Rs. 600. Three of the students have no savings at all and each of the others have at least Rs. 250 including Nihar, who has exactly Rs. 1300. The largest amount, in Rs., that any one student could have is

A) 3250 B) 3450
C) 3650 D) 3850
 
Answer & Explanation Answer: B) 3450

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Q:

Two equal circles intersect such that each passes through the centre of the other. If the length of the common chord of the circles is 10√3 cm, then what is the diameter of the circle?

A) 10 cm B) 15 cm
C) 20 cm D) 30 cm
 
Answer & Explanation Answer: C) 20 cm

Explanation:

Let there be 2 circles with centre O1 and OAB is the common chord

Since both passes through the center of each other as shown in figure

So O1O is the radius of both

Let O1O = r = AO1= AO

AX = AB / 2 = 5√3 cm (since OX perpendicular to chord bisects it)

AOO1 forms an equilateral triangle with on side = radius = r

Sin 60 = √3/2 = AX / AO = 5√3/r

So r = 10 cm

So diameter = 20 cm

 

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