5555+ Aptitude and Reasoning Questions, Answers With Explanation

Q:

The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 kmph. Then find the speed of faster train ?

A) 68 kmph	B) 52 kmph
C) 76 kmph	D) 50 kmph

Answer & Explanation Answer: A) 68 kmph

Explanation:

Let the speed of the faster train be 'X' kmph,
Then their relative speed= X - 48 kmph
To cross slower train by faster train,
Distance need to be cover = (400 + 600)m = 1 km. and
Time required = 180 sec = 180/3600 hr = 1/20 hr.
Time = Distance/Speed
=> 1/20 = 1/(x-48)
X = 68 kmph

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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14 9593

Q:

A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ?

A) 10 sec	B) 48 sec
C) 36 sec	D) 56 sec

Answer & Explanation Answer: C) 36 sec

Explanation:

Given speed of jogger = 9 kmph
Speed of train = 45 kmph
As they are in same direction,
Relative speed = 45 - 9 = 36 kmph = 36x5/18 = 10 m/s
Distance = 240 + 120 = 360 mts
Time = distance/speed = 360/10 = 36 sec.

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Filed Under: Problems on Trains
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2 4765

Q:

The arithmetic mean of the following numbers 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6 and 7, 7, 7, 7, 7, 7, 7 is ?

A) 6	B) 9
C) 7	D) 5

Answer & Explanation Answer: D) 5

Explanation:

Arithmatic mean = sum/members

=> (1x1 + 2x2 + 3x3 + 4x4 + 5x5 + 6x6 + 7x7) / (1 + 2 + 3 + 4 + 5 + 6 + 7)

=> 140/28 = 5

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Filed Under: Arithmetical Reasoning
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4 5785

Q:

There are 100 students in 3 sections A, B and C of a class. The average marks of all the three sections was 84. The average of B and C was 87.5 and the average marks of students in A section was :

A) 20	B) 35
C) 54	D) 40

Answer & Explanation Answer: A) 20

Explanation:

Numbers of students in section A = x
∴ Numbers of students in section B and C = (100 – x)
∴ x 70 + (100 – x) 87.5 = 84 100
=> 70x + 87.5 100 – 87.5x = 8400
=> 8750 – 17.5x = 8400
=> 17.5x = 8750 – 8400 => x = 20.

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Filed Under: Average
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24 10039

Q:

When I went back to my hometown three years ago, I found that a lot of changes ______.

A) were taken place	B) are taken place
C) had taken place	D) have taken place

Answer & Explanation Answer: C) had taken place

Explanation:

Since he is telling about the thing that had happened in past.

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Filed Under: Analogy
Exam Prep: AIEEE , GRE , TOEFL

10 8037

Q:

The compound interest earned by Sunil on a certain amount at the end of two years at the rate of 8% p.a. was Rs.2828.80. Find the total amount that Sunil got back at the end of two years in the form of principal plus interest earned ?

A) Rs. 11828.80	B) Rs. 19828.80
C) Rs. 9828.80	D) Rs. 19328.80

Answer & Explanation Answer: B) Rs. 19828.80

Explanation:

Let the sum be Rs. P
P{ ${(1 + \frac{8}{100})}^{2}$ - 1 } = 2828.80

It is in the form of $a^{2} - b^{2} = (a + b) (a - b)$

P(8/100)(2 + 8/100) = 2828.80

P = 2828.80 / (0.08)(2.08)

= 1360/0.08 = 17000

Principal + Interest = Rs. 19828.80

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Filed Under: Compound Interest
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12 6092

Q:

The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles ?

A) 2413 sq.m	B) 1234 sq.m
C) 4312 sq.m	D) 2143 sq.m

Answer & Explanation Answer: C) 4312 sq.m

Explanation:

Let the radii of the smaller and the larger circles be 's' m and 'l' m respectively.

$2 πs$ = 264 and $2 πl$ = 352

s = $\frac{264}{2 π}$ and l = $\frac{352}{2 π}$

Difference between the areas = $π l^{2} - π s^{2}$

= $π (\frac{176^{2}}{π^{2}} - \frac{132^{2}}{π^{2}})$

= $\frac{1762}{π} - \frac{1322}{π}$

= (176 - 132)(176 + 132) / $π$

= (44 x 308) / (22/7) = 4312 sq.m

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Filed Under: Volume and Surface Area
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18 8094

Q:

The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 50% profit ?

A) Rs. 660	B) Rs. 560
C) Rs. 1060	D) Rs. 960

Answer & Explanation Answer: D) Rs. 960

Explanation:

Let C.P. = Rs. C.
Then, 832 - C = C - 448
2C = 1280 => C = 640
Required S.P. = 150% of Rs. 640 = 150/100 x 640 = Rs. 960.

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Filed Under: Profit and Loss
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48 23161

Aptitude and Reasoning Questions

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Non Verbal Reasoning

Quantitative Aptitude - Arithmetic Ability

Quantitative Aptitude - Data Interpretation

Verbal Reasoning - Logical Deduction

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