5555+ Aptitude and Reasoning Questions, Answers With Explanation

Q:

Other things being equal, would an investor prefer an interest rate of 10.5% compounded monthly or 11% compounded annually for a two-year investment?

A) 1232	B) 1243
C) 1254	D) 1262

Answer & Explanation Answer: A) 1232

Explanation:

i=j/m

FV= PV(1+ i)^n

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0 2832

Q:

if $\log_{10} 5 + \log (5 x + 1) = \log_{10} (x + 5) + 1, t h e n x i s e q u a l t o$

A) 1	B) 3
C) 5	D) 10

Answer & Explanation Answer: B) 3

Explanation:

$\log_{10} 5 + \log (5 x + 1) = \log_{10} (x + 5) + 1$

$\log_{10} [5 (5 x + 1)] = \log_{10} [10 (x + 5)]$

$5 (5 x + 1) = 10 (x + 5)$

5x+1=2x+10

3x=9

x=3

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28 5825

Q:

What annual payment will discharge a debt of Rs.7620 due in 3years at $16 \frac{2}{3}$ % per annum interest?

A) 5430	B) 4430
C) 3430	D) 2430

Answer & Explanation Answer: C) 3430

Explanation:

Let each installment be Rs.x. Then,

(P.W. of Rs.x due 1 year hence) + (P.W of Rs.x due 2 years hence) + (P.W of Rs. X due 3 years hence) = 7620.

$[\frac{x}{(1 + \frac{50}{3 x 100})}] + [\frac{x}{1 + {(\frac{50}{3 x 100})}^{2}}] + [\frac{x}{1 + {(\frac{50}{3 x 100})}^{3}}] = 7620$

$\frac{6 x}{7} + \frac{36 x}{49} + \frac{216 x}{343} = 7620$

$294 x + 252 x + 216 x = 7620 x 343$

=> x = 3430

Amount of each installment = Rs.3430

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78 25778

Q:

A sum of money amounts to Rs.6690 after 3 years and to Rs.10,035 after 6 years on compound interest.find the sum.

A) 4360	B) 4460
C) 4560	D) 4660

Answer & Explanation Answer: B) 4460

Explanation:

Let the sum be Rs.P.then
P(1+R/100)^3=6690…(i) and P(1+R/100)^6=10035…(ii)
On dividing,we get (1+R/100)^3=10025/6690=3/2.
Substituting this value in (i),we get:
P*(3/2)=6690 or P=(6690*2/3)=4460
Hence,the sum is rs.4460.

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253 71442

Q:

A certain sum amounts to Rs.7350 in 2 years and to Rs.8575 in 3 years.find the sum and rate percent

A) 3400	B) 4400
C) 5400	D) 6400

Answer & Explanation Answer: C) 5400

Explanation:

Interest for 1 year is the same whether it's simple interest or the compound interest.

Now interest of third year = 8575 - 7350 = 1225; means principal for this interest is 7350 if comound interest is takenIf 7350 is the principal interest = 1225

if 100 is the principal interest =(1225/7350) * 100 = 50/3 %

When a thing increases for two successive times the overall increase on initial amount = a + b + (a * b)/100

Therefore overall interest for two years = 50/3 + 50/3 + [(50/3)*(50/3)]/100 = 325/9 %

Therefore amount after 2 years = 100 + 325/9 = 1225/9

If 1225/9 is the amount principal =100

if 7350 is the amount principal =(900/1225)*7350 =5400

So sum = 5400; Rate = 50/3 %

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67 33017

Q:

Divide Rs. 1301 between A and B, so that the amount of A after 7 years is equal to the amount of B after 9 years, the interest being compounded at 4% per annum.

A) Rs.625	B) Rs.626
C) Rs.286	D) Rs.627

Answer & Explanation Answer: A) Rs.625

Explanation:

Let the two parts be Rs. x and Rs. (1301 - x).

$x {(1 + \frac{4}{100})}^{7} = (1301 - x) {(1 + \frac{4}{100})}^{9}$

$\frac{x}{(1301 - x)} = {(1 + \frac{4}{100})}^{2} = (\frac{26}{25} * \frac{25}{26})$

=> 625x=676(1301-x)

1301x=676 x 1301x=676.
So,the parts are rs.676 and rs.(1301-676)i.e rs.676 and rs.625

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33 24724

Q:

The difference between the compound interest and the simple interest accrued on an amount of Rs. 18,000 in 2 years was Rs. 405. What was the rate of interest p.c.p.a. ?

A) 12%	B) 13%
C) 14%	D) 15%

Answer & Explanation Answer: D) 15%

Explanation:

Let the rate be R% p.a. Then,

$[1800 {(1 + \frac{R}{100})}^{2} - 1800] - (\frac{1800 * R * 2}{100}) = 405$

$1800 [\frac{{(100 + R)}^{2}}{10000} - 1 - \frac{2 R}{100}] = 405$

$1800 [\frac{{(100 + R)}^{2} - 10000 - 200 R}{10000}] = 405$

$\Leftrightarrow$

$\frac{9}{5} * R^{2} = 405 \Leftrightarrow R^{2} = (\frac{405 * 5}{9}) = 225 \Leftrightarrow R = 15$
Rate = 15%.

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21 24075

Q:

The difference between the compound interest and simple interest on a certain sum at 10% per annum for 2 years is Rs. 631. Find the sum.

A) 60100	B) 61100
C) 62100	D) 63100

Answer & Explanation Answer: D) 63100

Explanation:

Let the sum be Rs. x. Then,
C.I. = x ( 1 + ( 10 /100 ))^2 - x = 21x / 100 ,
S.I. = (( x * 10 * 2) / 100) = x / 5
(C.I) - (S.I) = ((21x / 100 ) - (x / 5 )) = x / 100
( x / 100 ) = 632 * x = 63100.
Hence, the sum is Rs.63,100.

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27 23939

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