Aptitude and Reasoning Questions

Q:

At what rate of compound interest per annum will a sum of rs.1200 becomes rs.1348.32 in 2 years

A) 66%% B) 6.5%
C) 7% D) 7.5%
 
Answer & Explanation Answer: A) 66%%

Explanation:

rate=r%

1200 (1+r/100)^2=1348.32

r=6%

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Filed Under: Simple Interest
Exam Prep: GRE
Job Role: Analyst

42 32594
Q:

In the following question, select the related letter pair from the given alternatives.

 

MRQ : PUT : : ?  :  ?

 

A) NOT : MNS B) FRY : IUB
C) PEG : RGI D) SAP : QYN
 
Answer & Explanation Answer: B) FRY : IUB

Explanation:
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Filed Under: Analogy
Exam Prep: Bank Exams

1 32591
Q:

In the following question, select the related word pair from the given alternatives.

Wood : Door : : ? : ?

A) Car : Truck   B) Table : Window
C) Clay : Statue D) Wood : Plastic
 
Answer & Explanation Answer: C) Clay : Statue

Explanation:
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Filed Under: Analogy
Exam Prep: Bank Exams

0 32577
Q:

In the following question, select the related letter pair from the given alternatives.

UCG : WEI : : ? : ?

A) RPC : TRE B) PWC : RYD
C) JLR:KNT D) LPJ:NQL
 
Answer & Explanation Answer: A) RPC : TRE

Explanation:
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Filed Under: Analogy

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Q:

In the following question, select the related word pair from the given alternatives.

 

Ohm : Resistance : : ? : ?

 

A) Temperature : Degree B) Hectare : Area
C) Energy : Watt D) Current : Ampere
 
Answer & Explanation Answer: B) Hectare : Area

Explanation:
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Filed Under: Analogy
Exam Prep: Bank Exams

1 32573
Q:

If 1.5x = 0.04y, then the value of ( (y - x) / (y+x) ) is :

A) 73/77 B) 7.3/77
C) 730/77 D) 7300/77
 
Answer & Explanation Answer: A) 73/77

Explanation:

x / y  = 0.04 / 1.5 = 4 / 150 = 2 / 75.

= > ( (y - x) / (y+x) ) = (1 - (x / y)) / ( 1 + ( x / y)) = (1 - 2/75) / (1 + 2/75) = 73/77...

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Filed Under: Decimal Fractions

83 32558
Q:

If 18$2 = 10, 8$4 = 6 and 12$18 = 15, then find the value of 7$9 = ?

 

A) 12   B) 20
C) 8 D) 18
 
Answer & Explanation Answer: C) 8

Explanation:
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Filed Under: Coding and Decoding
Exam Prep: Bank Exams

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Q:

In how many different ways can the letters of the word 'DETAIL' be arranged in such a way that the vowels occupy only the odd positions?

A) 36 B) 25
C) 42 D) 120
 
Answer & Explanation Answer: A) 36

Explanation:

There are 6 letters in the given word, out of which there are 3 vowels and 3 consonants.

 

Let us mark these positions as under: 

                                                      (1) (2) (3) (4) (5) (6) 

Now, 3 vowels can be placed at any of the three places out 4, marked 1, 3, 5.  

Number of ways of arranging the vowels = 3P3 = 3! = 6.

 

Also, the 3 consonants can be arranged at the remaining 3 positions. 

Number of ways of these arrangements = 3P3 = 3! = 6. 

Total number of ways = (6 x 6) = 36.

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