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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

Complete the Analogy?

 

Grain : Stock :: Stick : ?

A) Bundle B) String
C) Collection D) Heap
 
Answer & Explanation Answer: A) Bundle

Explanation:

Here the relation between the given words is that the second word is the collection of the first word.

As the collection of grains is called Stock, similarly, the collection of sticks is called as Bundle.

 

Hence, Grain : Stock :: Stick : Bundle.

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Filed Under: Analogy
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

17 89488
Q:

In a row of boys, If A who is 10th from the left and B who is 9th from the right interchange their positions, A becomes 15th from the left. How many boys are there in the row ?

A) 23 B) 31
C) 27 D) 28
 
Answer & Explanation Answer: A) 23

Explanation:

Clearly, A’s new position is 15th from the left. But this is the same as B’s earlier position which is 9th from the right.

 

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Filed Under: Number, Ranking and Time Sequence Test

729 89260
Q:

Insert the missing number.

3, 7, 6, 5, 9, 3, 12, 1, 15, (....)

A) 18 B) 13
C) -1 D) 3
 
Answer & Explanation Answer: C) -1

Explanation:

There are two series, beginning respectively with 3 and 7. In one 3 is added and in another 2 is subtracted.

The next number is 1 - 2 = -1.

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Filed Under: Odd Man Out

73 89157
Q:

Arrange the given words in a meaningful sequence.

1. Rainbow     2. Rain     3. Sun     4. Happy     5. Child

A) 4, 2, 3, 5, 1 B) 2, 3, 1, 5, 4
C) 4, 5, 1, 2, 3 D) 2, 1, 4, 5, 3
 
Answer & Explanation Answer: B) 2, 3, 1, 5, 4

Explanation:

The Correct Sequence is:

Rain    Sun    Rainbow    Child    Happy

   2          3           1                5           4

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Filed Under: Logical Sequence of Words

22 88942
Q:

Two dice are tossed. The probability that the total score is a prime number is:

A) 5/12 B) 1/6
C) 1/2 D) 7/9
 
Answer & Explanation Answer: A) 5/12

Explanation:

Clearly, n(S) = (6 x 6) = 36.

Let E = Event that the sum is a prime number.

Then E= { (1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4,3),(5, 2), (5, 6), (6, 1), (6, 5) }

n(E) = 15.

P(E) = n(E)/n(S) = 15/36 = 5/12.

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Filed Under: Probability

220 88485
Q:

In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 60 questions and secures 130 marks, the no of questions he attempts correctly is :

A) 35 B) 38
C) 40 D) 42
 
Answer & Explanation Answer: B) 38

Explanation:

Let the number of correct answers be X.

Number of incorrect answers = (60 – X).

4x – (60 – x) = 130

=> 5x = 190 

=> x = 38

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Filed Under: Simplification

265 88129
Q:

In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by:

A) 5.4m B) 4.5m
C) 5m D) 6m
 
Answer & Explanation Answer: D) 6m

Explanation:

A : B = 100 : 90.

 

A : C = 100 : 87.

 

B/C = (B/A*A/C) = (90/100*100/87) = 30/29

 

When B runs 30 m, C runs 29 m.

 

When B runs 180 m, C runs (29/30*180)m =174m

 

 B beats C by (180 - 174) m = 6 m.

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Filed Under: Races and Games

104 88101
Q:

23-[24-25-(26-27-28¯)]=?

 

 

A) -2 B) -3
C) -1 D) 1
 
Answer & Explanation Answer: C) -1

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

18 87783