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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

A room is half as long again as it is broad. The cost of carpeting the at Rs. 5 per sq.m is Rs. 270 and the cost of papering the four walls at Rs. 10 per sq.m is Rs. 1720. If a door and 2 windows occupy 8 sq. m, find the dimensions of the room.

A) b=6; l=18; H=6 B) b=5; l=6; H=18
C) l=6; b=18; H=15 D) l=5; b=18; H=18
 
Answer & Explanation Answer: A) b=6; l=18; H=6

Explanation:

Let breadth = x metres, length = 3x metres, height = H metres. 

Area of the floor=(Total cost of carpeting)/(Rate) = (270/5) sq.m = 54 sq.m 

x×3x2=54⇒x2=54×2⇒x=6  

So, breadth = 6 m and length =362 = 9 m.

Now, papered area = (1720/10) =  172 sq.m 

Area of 1 door and 2 windows = 8 sq.m 

Total area of 4 walls = (172 + 8) sq.m = 180 sq.m 

2×9+6H=180⇒H=6

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

33 26745
Q:

Tract of land used for raising crops or livestock.

A) A field B) A farm
C) Both A & B D) None of the above
 
Answer & Explanation Answer: C) Both A & B

Explanation:

A tract of land used for raising crops or livestockcan be called a field or a farm.

 

a_tract_of_land_used_for_raising_crops_or_livestock1559215948.jpg image

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Filed Under: Alphabet Test
Exam Prep: TOEFL , GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: IT Trainer , Database Administration , Bank PO , Bank Clerk , Analyst

49 26711
Q:

If the ratio of the ages of two friends A and B is in the ratio 3 : 5 and that of B and C is 3 : 5 and the sum of their ages is 147, then how old is B?

A) 27 Years B) 75 Years
C) 45 Years D) 49 Years
 
Answer & Explanation Answer: C) 45 Years

Explanation:

The ratio of the ages of A and B is 3 : 5.
The ratio of the ages of B and C is 3 : 5.

B's age is the common link to both these ratio. Therefore, if we make the numerical value of the ratio of B's age in both the ratios same, then we can compare the ages of all 3 in a single ratio.

The can be done by getting the value of B in both ratios to be the LCM of 3 and 5 i.e., 15.

The first ratio between A and B will therefore be 9 : 15 and
the second ratio between B and C will be 15 : 25.

Now combining the two ratios, we get A : B : C = 9 : 15 : 25.

Let their ages be 9x, 15x and 25x.
Then, the sum of their ages will be 9x + 15x + 25x = 49x

The question states that the sum of their ages is 147.
i.e., 49x = 147 or x = 3.

Therefore, B's age = 15x = 15*3 = 45

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Filed Under: Ratios and Proportions
Exam Prep: GRE

59 26710
Q:

In the following question, select the odd word pair from the given alternatives.

 

A) Sister – Female B) Male – Father
C) Brother – Male D) Grandmother – Female
 
Answer & Explanation Answer: B) Male – Father

Explanation:
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Filed Under: Odd Man Out
Exam Prep: Bank Exams

2 26702
Q:

A man purchased a cow for Rs. 3000 and sold it the same day for Rs. 3600, allowing the buyer a credit of 2 years. If the rate of interest be 10% per annum, then the man has a gain of:

A) 0% B) 5%
C) 7.5% D) 10%
 
Answer & Explanation Answer: A) 0%

Explanation:

C.P = Rs.3000 

S.P =Rs. [3600 x 10] / [100+(10 x 2)] = Rs.3000 

Gain =0%

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Filed Under: True Discount

35 26700
Q:

In Arun's opinion, his weight is greater than 65 kg but leas than 72 kg. His brother does not agree with Arun and he thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all of them are correct in their estimation, what is the average of diferent probable weights of Arun ?

A) 55.5 kg B) 66.5 kg
C) 77.5 kg D) 88.5 kg
 
Answer & Explanation Answer: B) 66.5 kg

Explanation:

Let Arun's weight be X kg.

According to Arun, 65 < X < 72.

According to Arun's brother, 60 < X < 70.

According to Arun's mother, X < 68.

The values satisfying all the above conditions are 66 and 67.

Required average = (66 + 67) / 2 = 66.5 kg

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Filed Under: Average

21 26678
Q:

If the mathematical operator '/' means 'x', '+' means '-', 'x' means '+' and '-' means '/', then

 

24 + 48 - 12 x 4 / 2 = ?

A) 6 B) -6
C) 16 D) 28
 
Answer & Explanation Answer: D) 28

Explanation:
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Filed Under: Coding and Decoding
Exam Prep: Bank Exams

0 26663
Q:

What will come in place of the question mark (?) in the given question?

1.5 % of 4600 + 2.8% of 2000 - 109 = ?

A) 32 B) 28
C) 12 D) 16
 
Answer & Explanation Answer: D) 16

Explanation:

1.5 % of 4600 + 2.8% of 2000 - 109 = ? ? = 16

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Filed Under: Number Series

0 26650