Aptitude and Reasoning Questions

Q:

A man wants to sell his scooter .There are two offers one at Rs12000 cash and other at a credit of Rs12880 to be paid after 8 months ,money being at 18% per annum which is better offer?

A) Rs.12880 B) Rs.12000
C) Both are equally good D) None of the above
 
Answer & Explanation Answer: B) Rs.12000

Explanation:

PW of Rs.12,880 due 8 months hence  

= Rs. [12880 x 100] / [100+(18 x 8/12)] =Rs.11500 

Clearly 12000 in cash is a better offer.

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Filed Under: True Discount

12 24143
Q:

Find the volume (in cub.cm) of a hemisphere of diameter 28 cm.

 

A) 4789.67   B) 3675  
C) 2732 D) 5749.33
 
Answer & Explanation Answer: D) 5749.33

Explanation:
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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

1 24126
Q:

In a certain code language STUDENT is written as TUTDNES.How will SOURCES be writte in that code language?

A) SOURCES B) SUORECS
C) SRUOCES D) SOURSEC
 
Answer & Explanation Answer: B) SUORECS

Explanation:

- There are 7 letters in the word

- The middle letter has been left intact

- The first and the last letters  of the word have interchanged their position. Similarly, the second and the third letters and the fifth and sixth letters have interchanged their position.

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Filed Under: Coding and Decoding

141 24094
Q:

Select the option that means 'Big Clever Parrot' according to the following Venn diagram.

 

 

 

A) M B) C
C) B D) F
 
Answer & Explanation Answer: B) C

Explanation:
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Filed Under: Image Analysis
Exam Prep: Bank Exams

0 24050
Q:

In order to obtain an income of Rs. 650 from 10% stock at Rs. 96, one must make an investment of:

A) 3100 B) 6240
C) 6500 D) 9600
 
Answer & Explanation Answer: B) 6240

Explanation:

To obtain Rs. 10,  investment = Rs. 96.

 

To obtain Rs. 650, investment = Rs.96*65010 = Rs. 6240.

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Filed Under: Stocks and Shares

21 24039
Q:

Find the appropriate relation for quantity1 and quantity2 in the following question:

Quantity 1: In an examination, Ankita scored 35 marks less than Puneeta. Puneeta scored 65 more marks than Meenakshi. Rakhi scored 115 marks, which is 20 marks more than Meenakshi's. Simpy scored 108 marks less than the maximum marks of the test. What approximate percentage of marks did Simpy score in the examination, if she got 67 marks more than Ankita?

Quantity 2: The length of a rectangle is increased by 60%. By what percent would the width have to be decreased to maintain the same area?

A) Quantity1 < Quantity2 B) Quantity1 ≤ Quantity2
C) Quantity1 ≥ Quantity2 D) Quantity1 > Quantity2
 
Answer & Explanation Answer: D) Quantity1 > Quantity2

Explanation:

Quantity1-
Rakhi’s marks= 115
Meenakshi’s marks= 115 - 20 = 95
Puneeta’s marks= 95 + 65= 160
Ankita’s marks=160 - 35= 125
Simpy’s marks= 125+ 67= 192
Total maximum marks= 192 + 108= 300
Required percentage marks of Simpy
192300×100=64%
Quantity2-
Let length and breadth be 100.

After increase in length it become 160, then
reduction in breadth be ‘x’
Now, 160*x= 100*100
Hence, x = 10000160=62.5

100-62.5=37.5%

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2 24032
Q:

Three persons A, B and C are standing in a queue. There are five persons between A and B and eight persons between B and C. If there be three persons ahead of C and 21 persons behind A, what could be the minimum number of persons in the queue?

A) 41 B) 40
C) 28 D) 27
 
Answer & Explanation Answer: C) 28

Explanation:

Three persons A, B, C can be arranged in a queue in six different ways, ie ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements, ie CBA and CAB.

 

We may consider the two cases as under:

Case I:  3C8B5A21

 

Clearly, number of persons in the queue = (3+1+8+1+5+1+21=) 40

 

Case II:  3C A5B

 

Number of persons between A and C                  

 

= (8 - 6) = 2   

[C8B A21B]

 

Clearly number of persons in the queue = (3+1+2+1+21) = 28

 

Now, 28 < 40. So, 28 is the minimum number of persons in the queue.                                                     

 

 

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168 24031
Q:

H.C.F of 4 x 27 x 3125,  8 x 9 x 25 x 7  and   16 x 81 x 5 x 11 x 49 is

A) 180 B) 360
C) 540 D) 1260
 
Answer & Explanation Answer: A) 180

Explanation:

4×27×3125=22×33×55

8×9×25×7=23×32×52×7

16×81×5×11×49=24×34×5×72×11

Therefore, H.C.F = 22×32×5 = 180

 

 

\inline \fn_jvn \therefore   \inline \fn_jvn H.C.F =2^{2}\times 3^{2}\times 5=180

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Filed Under: HCF and LCM

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