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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

The calendar of the year 2024 can be used again in the year?

A) 2030 B) 2052
C) 2048 D) 2036
 
Answer & Explanation Answer: B) 2052

Explanation:

NOTE :

Repetition of leap year ===> Add +28 to the Given Year.

Repetition of non leap year

Step 1 : Add +11 to the Given Year. If Result is a leap year, Go to step 2.

Step 2:  Add +6 to the Given Year.

 

Solution : 

Given Year is 2024, Which is a leap year.

So, Add +28 to the given year (i.e 2024 + 28) = 2052

Therfore, The calendar of the year 2024 can be used again in the year 2052.

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Filed Under: Calendar

77 22978
Q:

Find the length of the longest pole that can be placed in a room 12 m long 8m broad and 9m high.

A) 14m B) 15m
C) 16m D) 17m
 
Answer & Explanation Answer: D) 17m

Explanation:

Length of longest pole = Length of the diagonal of the room

 

122+82+92=289 = 17m

 

 

 

 

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Filed Under: Volume and Surface Area

35 22971
Q:

What percent of a day is 3 hours?

A) 14.9% B) 12.5%
C) 15.6%% D) 11.4%
 
Answer & Explanation Answer: B) 12.5%

Explanation:

Let p% of a day is 3 hrs.

We know that a day has 24 hrs.

=> p x 24/100 = 3

=> p = 300/24

=> p = 12.5%

 

Hence, 3 hrs is 12.5% of a day.

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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25 22968
Q:

There are 7 non-collinear points. How many triangles can be drawn by joining these points?

A) 10 B) 30
C) 35 D) 60
 
Answer & Explanation Answer: C) 35

Explanation:

A triangle is formed by joining any three non-collinear points in pairs.

 

There are 7 non-collinear points

 

The number of triangles formed = 7C3 = 35

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Filed Under: Permutations and Combinations

15 22954
Q:

The simple interest at y% for 'y' years will be Rs. y on a sum. Find the principal amount.


 

A) 100/y B) 100 x y
C) 100y2 D) 100 ÷ y2
 
Answer & Explanation Answer: A) 100/y

Explanation:
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Filed Under: Simple Interest
Exam Prep: Bank Exams

2 22947
Q:

How many arrangements of the letters of the word ‘BENGALI’ can be made if the vowels are to occupy only odd places.

A) 720 B) 576
C) 567 D) 625
 
Answer & Explanation Answer: B) 576

Explanation:

There are 7 letters in the word Bengali of these 3 are vowels and 4 consonants.

 

There are 4 odd places and 3 even places. 3 vowels can occupy 4 odd places in 4P3 ways and 4 constants can be arranged in 4P4 ways.

 

Number of words =4P3  x 4P4= 24 x 24 = 576

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Filed Under: Permutations and Combinations

18 22947
Q:

A train moves with a speed of 108 kmph. Its speed in metres per second is :

A) 10.8 B) 18
C) 30 D) 38.8
 
Answer & Explanation Answer: C) 30

Explanation:

108 kmph = 108*[5/18] m/sec = 30 m / s.

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Filed Under: Problems on Trains

42 22928
Q:

How long will it take for a sum of money to grow from Rs.1250 to Rs.10,000, if it is invested at 12.5% p.a simple interest?

A) 65years B) 56years
C) 45years D) 57years
 
Answer & Explanation Answer: B) 56years

Explanation:

Simple interest is given by the formula SI = (pnr/100), where p is the principal, n is the numberof years for which it is invested, r is the rate of interest per annum

 

In this case, Rs. 1250 has become Rs.10,000.

 

Therefore, the interest earned = 10,000 – 1250 = 8750.

 

8750 = [(1250 x n x 12.5)/100]

 

=> n = 700 / 12.5 = 56 years.

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Filed Under: Simple Interest
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Job Role: Bank PO

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