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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

Out of 120 students in aschool, 5% can play all the three games Cricket, Chess and Carroms. If so happens that the number of players who can play any and only two games is 30. The number of students who can play the Cricket alone is 40. What is the total number of those who can play Chess alone or Carroms alone ?

A) 45 B) 44
C) 46 D) 24
 
Answer & Explanation Answer: B) 44

Explanation:

k11483174138.jpg image

 

Given U=120

5% of 120 = 6

Therefore, Students who can play Chess alone or Carroms alone =  120 - (30+40+6)= 44

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Filed Under: Logical Venn Diagram
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97 18394
Q:

Ratio of the ages of Mahesh and Nilesh is 5 : x. Mahesh is 18 years younger to Ramesh. After nine years Ramesh will be 47 years old. If the difference between the ages of Mahesh and Nilesh is same as the age of Ramesh, what is the value of x ?

A) 11.8 B) 12.9
C) 13.7 D) 14.5
 
Answer & Explanation Answer: D) 14.5

Explanation:

Let the present ages of Mahesh, Nilesh and Ramesh be k, l and m respectively.
k/l = 5/x ------ (1)
k = m - 18 ------ (2)
m + 9 = 47 ------ (3)
k - l = m ----- (4)
(3) => m = 47 - 9 = 38 years
(2) => k = 38 -18 = 20 years
(1) => 20/l = 5/x => l = 4x
(4) => 4x - 20 = 38
=> 4x = 58 => x = 14.5

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Filed Under: Problems on Ages
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27 18392
Q:

Find the area of a square, one of whose diagonals is 3.8 m long

A) 7.22 B) 6.22
C) 4.22 D) 3.22
 
Answer & Explanation Answer: A) 7.22

Explanation:

Area of the square =12*diagonal2=12*3.8*3.8=7.22m2

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Filed Under: Area
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16 18388
Q:

If every seconds Saturday and all Sundays are holidays in a 30 days month beginning on Saturday, then how many working days are there in that month ? (Month starts from Saturday)

A) 25 B) 22
C) 24 D) 23
 
Answer & Explanation Answer: D) 23

Explanation:

As month begins on Saturday, so 2nd, 9th, 16th, 23rd, 30th days will be Sundays. While 8th and 22nd days are second Saturdays. Thus, there are 7 holidays in all.

Hence, no. of working days = 30 – 7 =23

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Filed Under: Calendar
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55 18376
Q:

Select the correct set that represents the following Venn diagram.

 

 

 

 

A) Office boys, government employees, educated person B) Males, fathers, doctors
C) Cat, toys, girl D) Doctors, human beings, cows
 
Answer & Explanation Answer: A) Office boys, government employees, educated person

Explanation:
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Filed Under: Logical Venn Diagram
Exam Prep: Bank Exams

2 18366
Q:

A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture ?

A) 5 lit B) 10 lit
C) 15 lit D) 20 lit
 
Answer & Explanation Answer: B) 10 lit

Explanation:

Number of liters of water in 150 liters of the mixture = 20% of 150 = 20/100 x 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 x (150 + P)
120 + 4P = 150 + P => P = 10 liters.

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Filed Under: Alligation or Mixture
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9 18331
Q:

The difference between two numbers is 1365. When larger number is divided by the smaller one, the quotient is 6 and the remainder is 15. The smaller number is ?

Answer

Let the numbers be x and 1365+x


Then 1365+x = 6x+15 


=> x = 270

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Subject: Problems on Numbers

35 18328
Q:

If log 64 = 1.8061, then the value of log 16 will be (approx)?

A) 1.9048 B) 1.2040
C) 0.9840 D) 1.4521
 
Answer & Explanation Answer: B) 1.2040

Explanation:

Given that, log 64 = 1.8061

 i.e log43=1.8061 

--> 3 log 4 = 1.8061

--> log 4 = 0.6020

--> 2 log 4 = 1.2040

⇒log42=1.2040

Therefore, log 16 = 1.2040

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Filed Under: Logarithms
Exam Prep: CAT
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51 18323